3:5 -> 6:10, 9:15, 12:20
8:10-> 4:5,16:20, 24:30
6:8 -> 3:4, 12:16, 30:40
6:18 -> 3:9, 12:36, 30:90
4:8 -> 1:2, 8:16, 12:24
Answer: The system will succeed when the first alarm rings or when the first one fails, but the second one rings. The probability of this is 0.98
The probability of system failure is 1-(probability of success)= 1-0.98= 0.02
Step-by-step explanation:
Factor the following:
2 x^3 + x^2 - 18 x - 9
Factor terms by grouping. 2 x^3 + x^2 - 18 x - 9 = (2 x^3 + x^2) + (-18 x - 9) = x^2 (2 x + 1) - 9 (2 x + 1):
x^2 (2 x + 1) - 9 (2 x + 1)
Factor 2 x + 1 from x^2 (2 x + 1) - 9 (2 x + 1):
(2 x + 1) (x^2 - 9)
x^2 - 9 = x^2 - 3^2:
(2 x + 1) (x^2 - 3^2)
Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3):
Answer: (x - 3) (x + 3) (2 x + 1) thus the Answer is C.
Answer: 452.16 or just 452 units^3
Step-by-step explanation:
V= πr^2*h
using 3.14 like the problem asks could effect what you're rounding to but either way pi(6)^2=113.04 *4= 452.16
To solve this problem you will need to use the cross product method:
1/16 of an hour → write 1 card
3/4 of an hour → write X cards
(3/4) ÷ (1/16) = X
0.75 ÷ 0.0625 = X
12 = X
Joey can write 12 Thank you cards in 3/4 of an hour.
There you go! I really hope this helped, if there's anything just let me know! :)
