The expression of the inequality word problems for each question is; As expressed below
<h3>How to express inequalities?</h3>
A) x is negative. This can be expressed as;
x < 0
B) y is non-negative. This can be expressed as;
y > 0
C) q is less than or equal to is expressed as; q ≤
D) d is between 2 and 1 is expressed as 1 < d < 2
E) t is not less than 5 is t ≥ 5
F) The negative of z is not greater than 3 is expressed as;
−z ≤ 3
G) The quotient of p and q is at most 6 is expressed as; p/q ≤ 6
H) The reciprocal of w is at least 9 is 1/w ≥ 9.
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3/4=0.75
0.75 would be equal to 3/4
The ratio of the area of ∆ABC to the area of ∆DEF is; 1:100.
<h3>What is the ratio of the area of ∆ABC to the area of ∆DEF?</h3>
Since, a major criterion for similarity and congruence of triangles is that the ratio of corresponding sides are equal.
On this note, since the task content suggest that the ratio of the perimeters is; 1:10, it follows from conventional mathematics that the ratio of their areas is given as; 1²:10²; 1:100.
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Answer:
Mass of the cat = 16800kg
Step-by-step explanation:
The volume of the box = its length * its breath * its height- 4m × 3m × 2m = 24
The standard density of water is 1000 Kg/
By Archimedes principle, the mass of a body floating body is equivalent to the mass of the volume liquid displaced
in this case we have
Mass of water displaced = Density of the water × Volume of the water displaced = 1000 Kg/ × 24 = 24000kg
The mass of the box = Box density × Box volume = 24 × 300kg/ = 7200 kg Hence the mass of water displaced = mass of the foating box + mass of th cat
24000kg = mass of cat +7200kg
mass of cat = 24000kg - 7200kg = 16800kg
Divide by 4 on both sides of the equations
