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4 years ago

Walk block.a)sentenceb)fragment

Mathematics

2 answers:

vampirchik [111]4 years ago

7 0

Fragment, because it has no subject

It also has to verbs... hope this helps you ♥︎☀︎☁︎♨︎

Lemur [1.5K]4 years ago

5 0

Answer is fragment because is fragment walk block

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FIFTY POINTS

Vlad [161]

Each of the four angles of a quadrilateral measures 90°.

Only 1 

we can construct using this condition.

as interior angle of quadrilateral and rectangle is 360°

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3 years ago

Which situation involves a change modeled by a positive number but an end result modeled by a negative number? A.Leo enters an e

Scrat [10]

The positive number but a negative result would be :

C. Irene is scuba diving at –30 feet. She swims 10 feet toward the surface to watch a school of fish.

The positive value is she swam 10 feet up to the surface, but she is still below the surface, which would be a negative result.

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4 years ago

Read 2 more answers

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

4 years ago

Hamburger Heaven is having a lunch special where customers buy one 1/4 pound cheeseburger and get one free. If they set aside 11

Sloan [31]

Answer: 459 cheeseburgers

Step-by-step explanation:

To find out the number of cheeseburgers that can be made, divide the amount of meat set aside by the amount of meat it takes to make one cheeseburger.

The amount of meat they have is:

= 114²/₃

= 344/3

Number of cheeseburgers is:

= 344/3 ÷ 1/4

= 344/3 * 4/1

= 1,376 / 3

= 458.67

= 459 cheeseburgers

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3 years ago

What is a double bond?

tatyana61 [14]

C two electrons with two atoms! <3

4 0

3 years ago

Walk block.a)sentenceb)fragment​

Walk block.a)sentenceb)fragment