1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svp [43]
3 years ago
12

A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A

quality control consultant is to select 4 of these workers for in-depth interviews. Suppose the selection is made in such a way that any particular group of 4 workers has the same chance of being selected as does any other group (drawing 4 slips without replacement from among 24).
Required:
a. How many selections result in all 5 workers coming from the day shift?
b. What is the probability that all 5 selected workers will be from the day shift?
c. What is the probability that all 5 selected workers will be from the same shift?
d. What is the probability that at least two different shifts will be represented among the selected workers?
e. What is the probability that at least one of the shifts will be unrepresented in the sample of workers?
Mathematics
1 answer:
Bezzdna [24]3 years ago
5 0
Yeah i think it’s A hope
You might be interested in
Bob's carpet cleaning company uses the equation y=22x+30 to calculate cost, y, to clean x numbers of rooms. Andy's carpet cleani
olga_2 [115]
Bob charges $140 
Andy charges $135 
Andy is cheaper
6 0
4 years ago
(2x2 - 4x + 7) + (3x3 - 9x)
Leviafan [203]
The answer is 20-13x
5 0
3 years ago
Need help anyone know how to do this
Dmitry_Shevchenko [17]
X Coordinate: (-3a + 3a)/2
0/2 = 0

Y Coordinate: (b + b)/2
2b/2 = b

Midpoint: (calculated x, calculated y)

In this case, the midpoint should be (0, b)
3 0
3 years ago
Indicate whether classical, empirical, or subjectiveprobability should be used to determine each of the following:
Snezhnost [94]

Answer:

Indicate whether classical, empirical, or subjective probability should be used to determine each of the following probabilities.

Step-by-step explanation:

a)  The probability that a certain model will win the beauty contest

is an example of which type of probability?

B - Classical  

b) "The probability that next card in the deck will be black" is an example of which type of probability?

 

B- Classical

c) "The probability that there will be at least 16 tropical storms this  summer" is an example of which type of probability?

B-Subjective  

d)  "There is a 0.30 probability of randomly selecting a student who has a part- time job " is an example of which type of probability?

A- Subjective

5 0
3 years ago
In 2008, the average household debt service ratio for homeowners was 13.2. The household debt service ratio is the ratio of debt
ankoles [38]

Answer:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

df=n-1=44-1=43  

p_v =P(t_{(43)}>1.436)=0.079  

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

Step-by-step explanation:

Information given

\bar X=13.88 represent the sample mean

s=3.14 represent the sample standard deviation

n=44 sample size  

\mu_o =13.2 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to conduct a hypothesis in order to check if the true mean has increased from 2008 , and the system of hypothesi are:  

Null hypothesis:\mu \leq 13.2  

Alternative hypothesis:\mu > 13.2  

The statistic for this case is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculating the statistic

Replacing the info given we got:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

P-value

The degrees of freedom are:

df=n-1=44-1=43  

Since is a right tailed test the p value is:  

p_v =P(t_{(43)}>1.436)=0.079  

Decision

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

8 0
4 years ago
Other questions:
  • Please help...Need help asap
    13·1 answer
  • Helpppppp please!!!!!
    8·1 answer
  • Prompt:
    15·2 answers
  • Can someome please help me?
    7·2 answers
  • On Monday, Brad biked 1 4 6 miles; Tuesday, 1 3 6 miles; Wednesday, 1 5 6 miles; and Thursday, 1 4 6 miles. On which day did he
    7·1 answer
  • Solve for x. Round to the nearest tenth, if necessary.
    11·1 answer
  • I need help what is the answer?
    6·2 answers
  • Please answer i’ll give brainliest !!!
    6·2 answers
  • Palawbhehrht awnser yes or mo
    13·1 answer
  • What value of g makes the equation true?<br><br> (x+7)(x-4)=x²+gx-28
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!