A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A
quality control consultant is to select 4 of these workers for in-depth interviews. Suppose the selection is made in such a way that any particular group of 4 workers has the same chance of being selected as does any other group (drawing 4 slips without replacement from among 24).
Required:
a. How many selections result in all 5 workers coming from the day shift?
b. What is the probability that all 5 selected workers will be from the day shift?
c. What is the probability that all 5 selected workers will be from the same shift?
d. What is the probability that at least two different shifts will be represented among the selected workers?
e. What is the probability that at least one of the shifts will be unrepresented in the sample of workers?
1 answer:
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Answer:
hello your answer is 21 y=21
Step-by-step explanation:
3 times -7 is 21- hope i helped
It is not a multiple of 8
Answer:
B
Step-by-step explanation:
- A 95% confidence level interval will have 0.52 (lower interval) & 0.68 (upper interval) which means that that if 90 individuals root for North HS then p value is 0.6 which will fall in the 95% confidence interval range.
- For the option B the p value will also be same as in case A hence B is true as an alternative hypothesis.
- We can calculate P value
Confidence Interval = p ± z 
see the attached figure to better understand the problem
we know that
If a and b are parallel lines
then
m∠1=m∠4 --------> by alternate exterior angles
m∠3+m∠4=
--------> by supplementary angles
so
m∠3+m∠1=
therefore
<u>the answer is the option</u>
m∠1 = 110° and m∠3 = 70°
