Write the expression to show 16 - the product of 2 and 3

Two numbers differ by 3. Their product is 28. Find the numbers.

Paraphin [41]

Answer:

Two solutions (-4,-7) and (4,7)

Step-by-step explanation:

x = y + 3

x*y = 28

(y+3)*y=28

y^2+3y-28=0

(y+7)(y-4)=0

y=-7, y=4

x=-4, x=7

3 0

1 year ago

Alina spent no more than $45 on gas for a road trip. The first gas station she used charged $3.50 per gallon and the second gas

Paraphin [41]

Answer: 3.50x + 4.00y ≤ 45

0 < y < 11.25

Step-by-step explanation:

$3.50x + 4.00y \leq 45\\\\\\\text{Subtract 3.50x from both sides:}\\4.00y\leq -3.50x+45\\\\\\\text{Divide everything by 4.00 (to isolate y):}\\\dfrac{4.00y}{4.00}\leq \dfrac{-3.50x}{4.00}+\dfrac{45}{4.00}\\\\\\y\leq-0.875x+11.25\\\\\\\text{Both x and y must be greater than zero, so:}\\0$

8 0

2 years ago

Read 2 more answers

Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr

Bad White [126]

Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

$x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}$

Where the determinant is D = b^2 - 4*a*c.

Now, if D>0

we have the square root of a positive number, which will be equal to a real number.

√D = R

then the solutions are:

$x = \frac{-b +- R }{2*a}$

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

$x = \frac{-b +- C*i }{2*a}$

We have two complex solutions.

If D = 0

√0 = 0

then:

$x = \frac{-b +- 0}{2*a} = \frac{-b}{2a}$

We have only one real solution (or two equal solutions, depending on how you see it)

3 0

2 years ago

Olivia used her past health history and information about her doctor visits to create this table to compare health costs with an

shusha [124]

The expected value of health care without insurance is $437.25.

The expected value of health care with insurance is $1,636.40.

<h3>What are the expected values?</h3>

The expected values can be determined by multiplying the respective probabilities by its associated costs.

The expected value of health care without insurance

= (1 x 0) + (0.32 x 1050) + (0.45 x $225)

= $437.25

The expected value of health care with insurance

= (1 x 1580) + (0.32 x 75) + (0.45 x $72)

= $1,636.40

Thus, The expected value of health care without insurance is $437.25.

The expected value of health care with insurance is $1,636.40.

Learn more about Expected value from:

brainly.com/question/13945225

#SPJ1

5 0

2 years ago

Complete #2 for me and show proof , will give brainliest to whose right .

Stells [14]

Answer:

X Y (X,Y)

-4 14. (-4,14)

-3 12. (-3,12)

-2 10. (-2,10)

-1 8. (-1,8)

0 6 (0,6)

1 4. (1,4)

2 2. (2,2)

4 0

1 year ago