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ale4655 [162]
3 years ago
8

As you can see I keep getting questions wrong.... Can you answer the last question?

Mathematics
1 answer:
aivan3 [116]3 years ago
4 0

Answer:

  y = 0

Step-by-step explanation:

It is always a good idea to look at the question and make some observations about it. Here, you might observe ...

  • all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
  • y is a factor of every exponent

The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.

__

To solve the equation, you can write it in terms of powers of 3.

  (3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)

  3^(-5y) = 3^(-15y)·3^(-4y)

  3^(-5y) = 3^(-19y)

  -5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3

  14y = 0 . . . . . . . . . . add 19y

  y = 0 . . . . . . . . . . . one solution

______

The rules of exponents we used are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

  1/a^b = a^-b

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Explain how to modify the graphs of f(x) and g(x) to graph the solution set to the following system of inequalities. How can the
Norma-Jean [14]

The graphs of f(x) and g(x) are transformed function from the function y = x^2

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<h3>How to modify the graphs</h3>

From the graph, we have:

f(x) = x^2 -3 and g(x) = -x^2 +2

To derive y < x^2 - 3, we simply change the equality sign in the function f(x) to less than.

To derive y > x^2 + 2, we perform the following transformation on the function g(x)

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  • Reflect across the x-axis
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  • Change the equality sign in the function g(x) to greater than

<h3>How to identify the solution set</h3>

The inequalities of the graphs become

y < x^2 - 3 and y > x^2 + 2

From the graph of the above inequalities (see attachment), we can see that the curves of the inequalities do not intersect.

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Read more about inequalities at:

brainly.com/question/25275758

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