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shtirl [24]
3 years ago
8

Help on numbers 1 and 2 any question, 1 or 2.

Mathematics
1 answer:
geniusboy [140]3 years ago
6 0
For #2 you would count how many where the red dashed line is! Which is 3! Then you would count where the blue dashed line is! Which is 4! So then it would be 4/3(4 over 3) For the slope! Hope this helps! :)
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A bag contains 4 red chips, 5 blue chips, and 6 green chips. If Susie selects a chip from
Anestetic [448]

Answer:

23%

Step-by-step explanation:

4 0
3 years ago
A blockbuster movie makes about $352,000,000 in the United States during its opening weekend. The same weekend another movie ope
Ivenika [448]

The combined revenue for the movies in scientific notation is  \$ 3.568 \times 10^8.

The given parameters;

  • <em>first revenue made from the movie, = $352,000,000</em>
  • <em>second revenue made from the movie, = $4,800,000</em>

The combined revenue from the movie is calculated by adding the two revenues together as shown below;

Total revenue = $352,000,000  +  $4,800,000

Total revenue = $356800000 =  \$ 3.568 \times 10^8

Thus, the combined revenue for the movies in scientific notation is  \$ 3.568 \times 10^8

Learn more here:brainly.com/question/18911739

5 0
3 years ago
Jus help im in a timed assigment
gogolik [260]
0.59
x 0.37
413
1770
2183
4 0
3 years ago
Round to the hundreds place: 722,356,964
maks197457 [2]
It might be hard at first to find the hundreds place. The answer is C:722,357,000



7 0
3 years ago
Read 2 more answers
A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
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