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stealth61 [152]
3 years ago
11

Help please! 10 points!

Mathematics
1 answer:
Zina [86]3 years ago
3 0
Let the number of chairs Gavin build per week is x and number of tables he builds per week is y.

It takes 4 hours to work on a chair and 10 hours to work on a table. So time taken to work on x chairs and y tables will be:

Time=4x+10y

Gavin wants to work for no more than 40 hours. So we can write the inequality as:

4x+10y \leq 40

It takes $10 worth of supplies to build a chair and $15 worth of supplies to build a table. So cost or worth of supplies for x chairs and y tables will be:

Cost=10x+15y

Gavin wants to spend no more than $80 on material. So we can write the inequality as:

10x+15y \leq 80

Thus the system of inequalities is:

4x+10y \leq 40
10x+15y \leq 80

We can observe the possible combinations from the graph of these inequalities, which is shown below:
a) 0 chair and 3 tables
b) 5 chairs and 2 tables
c) 8 chairs and 2 tables 

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