All categories

2 years ago

What is the greatest common factor for 840 and 440

Mathematics

1 answer:

Leni [432]2 years ago

5 0

.........................It is 40.

You might be interested in

Find the coefficient of the x^3 in the expansion of (2x-9)^5

il63 [147K]

Use the binomial theorem:

$\displaystyle (2x-9)^5 = \sum_{k=0}^5 \binom5k (2x)^{5-k}(-9)^k = \sum_{k=0}^5 \frac{5!}{k!(5-k)!} 2^5 \left(-\frac92\right)^k x^{5-k}$

The x ³ terms occurs for 5 - k = 3, or k = 2, and its coefficient would be

$\dfrac{5!}{2!(5-2)!} 2^5 \left(-\dfrac92\right)^2 = \boxed{6480}$

8 0

2 years ago

0.07 is closest to 0,1, or 1/2?

gulaghasi [49]

0 is the right answer.

3 0

3 years ago

Evaluate each expression if r= −3, s=4, and t= −7.

saul85 [17]

Answer:

a. $5$

b. $-1$

c. $132$

Step-by-step explanation:

Given:

$r =-3$ , $s = 4$ and $r = -7$

$\sqrt{s} +|r| \\ \sqrt{4} +|-3| \\ 2 +3 \\ 5$

$\frac{s -r}{t} \\ \frac{4 -(-3)}{-7} \\ \frac{4 +3}{-7} \\ \frac{7}{-7} \\ -1$

$2s^3 +r -t \\ 2(4)^3 +(-3) -(-7) \\ 2(64) -3 +7 \\ 128 -3 +7 \\ 132$

5 0

2 years ago

Use the given confidence interval limits to find the point estimate p^ and the margin of error E. 0.325

diamong [38]

Answer:

0.350

Step-by-step explanation:

Confidence interval = point estimate ± margin of error

Point estimate = Confidence interval - margin of error

To get the margin of error, we will take the average of the difference of the interval given. Given the confidence interval 0.325<p<0.375

Margin of error = 0.375-0.325/2

Margin of error = 0.050/2

Margin of error = 0.025

Using the interval of 0.375

Point estimate = 0.375 - 0.025

Point estimate = 0.350

3 0

3 years ago

What is the range

Elena-2011 [213]

C I believe the -2 part that was the one just looked it up on google XD hope it helped

7 0

2 years ago