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Shkiper50 [21]
3 years ago
12

80,057.8 + 181.15 plz and after this I will be posting a whole sheet but all of it is due tomorrow so help plz

Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

80238.95

Step-by-step explanation:

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A pitcher can hold 8 times as much as glass. The pitcher hold 64 ounces
Harlamova29_29 [7]

Answer:

The glass can hold 8. (I think)

Step-by-step explanation:

8 0
3 years ago
What is the value of the right rectangular prism
storchak [24]
Hello!

To find the area of a rectangular prism you do 2(lw + lh + wh)

Put in the values

2(9 * 2 + 9 * 6 + 2 * 6)

2(18 + 54 + 12)

2(84)

2 * 84 = 168

The answer is 168 cubic inches

Hope this helps!

6 0
3 years ago
Slope = 4, passing through (-6, 8)
Mademuasel [1]

The point slope form is y - 8 = 4(x + 6) and the slope intercept form would be y = 4x + 32.

In order to find this, we'll start with the base form of point-slope form.

y - y1 = m(x - x1) ----> Plug in the numbers

y - 8 = 4(x - -6) ----> Simplify

y - 8 = 4(x + 6)

Now to find slope intercept form, solve for y.

y - 8 = 4(x + 6) ----> distribute the 4

y - 8 = 4x + 24 -----> add 8 to both sides

y = 4x + 32

7 0
3 years ago
Help, I’m stuck. Thank you very much
ZanzabumX [31]
If you notice, the container is really just two circles, with a diameter of 4 each, and a square with sides of 10.5.

now, if we just get the area of each circle, keeping in mind their radius is half of the diameter, namely r = 2, and get the area of the 10.5x10.5 square, sum them up, that'd be the surface area of the container.

\bf \stackrel{\textit{2 circle's area}}{2(\pi r^2)}~~+~~\stackrel{\textit{area of the square}}{10.5\cdot 10.5}
\\\\\\
\stackrel{\textit{2 circle's area}}{2(\pi 2^2)}~~+~~\stackrel{\textit{area of the square}}{10.5\cdot 10.5}\implies 8\pi + 110.25
5 0
3 years ago
A 30ft electric line is suspended between the tops of two 20ft electric poles on level ground. The lowest point of the line is 5
Lilit [14]

Answer:

There is no distance between them

Step-by-step explanation:

For a 30 ft electric line to be placed between two 20ft electric poles, it would take 15 ft of the electric line to go down to about 5 ft above the ground and another 15 ft of the line to go to the top of the second electric pole. This means that a total of 30ft (15 ft + 15 ft) electric line would be needed which is all the cable we have.

For this to be possible then the poles must be adjacent to each other (i.e. no distance between them).

7 0
2 years ago
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