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ioda
3 years ago
7

How do you square a variable

Mathematics
1 answer:
77julia77 [94]3 years ago
8 0
To square means to multiply something by itself. A variable is a letter such as x. So a squared variable=x×x=x^2.
I hope that helped.
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I need help with this math question
djyliett [7]
Percent means per one hundred so we can say that:

p/100≈(28)/(28+81+45+63+35)  guessing with my old eyes :)

p/100≈28/252

p≈2800/252

p≈11.11%

So rounded to the nearest 5% you'd have:

p≈10%
5 0
3 years ago
What is the median of this set of data: 10, 11, 12, 12, 15, 19, 20, 21, and 22? Express your answer as an integer.
Rama09 [41]
15, median is the number in the middle, (i.e. median of 3, 4, 8, 9, 10, is 8.)
4 0
3 years ago
Read 2 more answers
A mixed number has a whole number part and a fractional part. <br>O A. True <br>O B. False​
scoray [572]

Answer: True

Step-by-step explanation:

The statement that a mixed number has a whole number part and a fractional part is true.

The mixed number is made up of a whole number, and a proper fraction. A mixed number simply means a number that is between any two whole numbers. Examples of mixed numbers are 4¾, 7½ etc.

6 0
3 years ago
Help plz..........................................................................................
Zarrin [17]
The answer is the last one
3 0
3 years ago
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Which components are a possible representation of vector w if the magnitude of vector -3w is ||-3w||=15?
Black_prince [1.1K]

Answer:

<-3,4>

<0,-5>

Step-by-step explanation:

|-3w| = 15

3|-w| = 3|w| = 15

|w| = \frac{15}{3}

|w| = 5

  • If vector w is represented by <1,-9>

Then |w| = \sqrt{(1)^{2}+(-9)^{2}}=\sqrt{1+81}=\sqrt{82}\neq5 .

Therefore this is not possible.

  • If vector w is represented by <-3,4>

Then |w| = \sqrt{(-3)^{2}+(4)^{2}}=\sqrt{9+16}=\sqrt{25}=5 .

Therefore this is possible.

  • If vector w is represented by <4,5>

Then |w| = \sqrt{(4)^{2}+(5)^{2}}=\sqrt{16+25}=\sqrt{41}\neq5 .

Therefore this is not possible.

  • If vector w is represented by <-5,-3>

Then |w| = \sqrt{(-5)^{2}+(-3)^{2}}=\sqrt{25+9}=\sqrt{34}\neq5 .

Therefore this is not possible.

  • If vector w is represented by <0,-5>

Then |w| = \sqrt{(0)^{2}+(-5)^{2}}=\sqrt{0+25}=\sqrt{25}=5 .

Therefore this is possible.

(NOTE : if z vector is represented by <x,y> then |z| = \mathbf{\sqrt{x^{2}+y^{2}}} )

4 0
3 years ago
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