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Yuliya22 [10]
2 years ago
8

If two water towers can hold 905 gallons of water, how much water can 11 water towers can hold

Mathematics
2 answers:
KonstantinChe [14]2 years ago
8 0

Answer:

4977.5

Step-by-step explanation:

kotykmax [81]2 years ago
7 0

Answer:

4977.5 gallons

Step-by-step explanation:

We can write a proportion to solve

2 towers            11 towers

---------------    = ---------------

905 gallons       x gallons

Using cross products

2 * x = 905 * 11

2x =9955

Divide each side by 2

2x/2 = 9955/2

x =4977.5 gallons

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Anyone know the answers to 1, 2, 3, 4, 5
muminat

Answer:

1. C. 1/4(4) + 1/4(9) (A, 1/4(13), is essentially C simplified (without figuring it out).)

2. G - -4

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Step-by-step explanation:

1.

1/4(4 + 9) <em>We can distribute 1/4 into 4 and 9.</em>

1/4(4) + 1/4(9) <em>Now while we have our answer, this can be further simplified.</em>

1/4(13) <em>What's on the left is the simplified 2-term equation.</em>

<em>So really, either C or A will be the answer. But due to the format of #3, I put C as my answer. B & D were out because there wasn't any extra multiplication.</em>

2.

-2/5(15 - 5) <em>Subtract 5 from 15 to get 10.</em>

-2/5(10) <em>Multiply -2/5 by 10 to get -20/5</em>

-20/5 <em>Divide -20 by 5 to get -4.</em>

-4, so G is the answer. <em>This was negative, so H & J were out to begin with. F was out as soon as I solved the problem.</em>

3.

-4(-5 + x) <em>Distribute -4 into -5 + x.</em>

-4(-5) + (-4)x, so A is the answer. <em>Don't get tricked! B may look right, but there should be a negative sign in front of the 5, hence why it's incorrect.</em>

4.

1/6(x + y) <em>Distribute 1/6 into x + y.</em>

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5.

Only 60(10 + 2) would have worked, so A is the answer. The tickets would have cost 720 dollars (600 + 120). <em>B would have equated to 624 (24 + 600), C would have been 132 (6 * 22), and D would have been 600. (10 * 60).</em>

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