Answer:
Class 7A collected 4.8 ounces of pure gold.
Step-by-step explanation:
<u>Key skills required are: Percentages, Multiplication</u>
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- We only need the information about Class 7A. They collected 40 oz that contains 12% gold.
- In other words, this means that 12% of that 40 oz gold sand is pure gold.
Here we have to do 12% x 40 to find the number of oz of pure gold. We first have to convert 12% into a decimal. Divide it by a 100 (or move the decimal point 2 places to the left) and you will get 0.12.
<em>Do 0.12 x 40 and you will get 4.8</em>
Therefore, there are 4.8 oz of pure gold in Class 7A's gold sand
By definition, the volume of a cylinder is given by:
V = π * r ^ 2 * h
Where,
r: cylinder radius
h: height
Clearing h we have:
h = (V) / (π * r ^ 2)
Substituting values:
h = (36π) / (π * 3 ^ 2)
h = (36π) / (9π)
h = (36π) / (9π)
h = 4 cm
Answer:
The height of the liquid will be in the new cylinder about:
h = 4 cm
