In a college math class of 50 students, 23 are boys and 27 are girls. On the final exam, 15 boys and 14 girls made an A. What is
the probability of choosing a boy or an A student if a student is chosen at random from the class?
1 answer:
boy or an A student is
29 made an A + 8 boys who did not make an A
37 who made an A and/or who is a boy
37/50
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Answer:
Which number lies halfway between:
a) 16 and 38 = 28
b) 259 and 361 =310
1004 and 2012?
=1058
The answer will be 1.09. Hope this will help you!
Answer:
0.4
Step-by-step explanation:
2 x (-0.2) + (-0.2) + 1
- 0.4 - 0.2 + 1
-0.6 + 1
= 0.4
Answer
Step-by-step explanation:
Law of sines: SinB/15 = SinA/BC
B = 90
A = 180-90-21=69°
BC= (15*SinA)/SinB = (15*sin69)/1 ≈ 14m
Answer:
$8
Step-by-step explanation:
1 flashdrive = $24
3 flash drives x $24 = $7
$80 - $72 = $8
