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murzikaleks [220]
3 years ago
7

The components of vector are ax and ay (both positive), and the angle that it makes with respect to the positive x axis is θ. Fi

nd the angle θ if the components of the displacement vector are (a) ax = 12 m and ay = 12 m, (b) ax = 20 m and ay = 12 m, and (c) ax = 12 m and ay = 20 m.
Mathematics
1 answer:
Andru [333]3 years ago
6 0

we can use formula

\theta=tan^{-1}(\frac{a_y}{a_x})

(a)

we are given

a_x=12,a_y=12

now, we can plug values

\theta=tan^{-1}(\frac{12}{12})

\theta=tan^{-1}(1)

\theta=\frac{\pi}{4}rad

(b)

we are given

a_x=20,a_y=12

now, we can plug values

\theta=tan^{-1}(\frac{12}{20})

\theta=tan^{-1}(\frac{3}{5})

\theta=30.96^{\circ \:}

(c)

we are given

a_x=12,a_y=20

now, we can plug values

\theta=tan^{-1}(\frac{20}{12})

\theta=tan^{-1}(\frac{5}{3})

\theta=59.03^{\circ \:}


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Amiraneli [1.4K]

Answer:

(3x^2+21x+33) / (x+5)

You can use long division:

(3x^2+21x+33)

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Please help me- thank you
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Answer:

a) The profit will be: Profit=y^2-99500

b) Since the profit is -9500 (negative) so, company will not gain any profit if they produce 300 bicycles.

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Revenue generated = 2y^2+10y+500

Find a polynomial that represent profits

The formula used for finding profit is:

Profit = Total \ Revenue - Total \ Cost\\Profit=  2y^2+10y+500 - (y^2+10y+100,000)\\Profit=  2y^2+10y+500 - y^2-10y-100,000\\Profit=2y^2-y^2+10y-10y+500-100,000\\Profit=y^2-99500

So, the profit will be: Profit=y^2-99500

If the company can produce bicycles y= 300

The profit will be:

Profit=y^2-99500\\Profit=(300)^2-99500\\Profit=90000-99500\\Profit=-9500

Since the profit is -9500 (negative) so, company will not gain any profit if they produce 300 bicycles.

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