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2 years ago

Which represents the solution to the absolute value equation? 3|2x+4|-1=11

1 answer:

5 0

The first step for absolute value equations is to isolate the expression contained within the absolute value bars:

3|2x+4|-1 = 11
3|2x+4| = 12
|2x+4| = 4

so |2x+4| is 4 units away from 0 on a number line, but we don't know in which direction -- negative or positive? you'll have two answers.

2x+4 = 4

AND

2x+4 = -4

solve both of those two step equations and you'll get

x = 0

AND

x = -4

so 0 and -4 are your solutions.

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Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

6 0

2 years ago

For which equation is y=7 a solution

irina1246 [14]

The answer would be B.

6 0

2 years ago

Bob is doing a quality test on machine bots , he tested 24 bolts that he randomly found that 5 were defective. Based on bob’s re

goldenfox [79]

Answer:

175

Step-by-step explanation:

5/24 = 0.208 percentage of defective bolts

scale up to 840 bolts by finding 20.8% of defective bolts

840*20.8 = 175

5 0

2 years ago

-6.25x>-38 3/4<br> solve the inequality

Nostrana [21]

Answer:

Step-by-step explanation:

-6.25x > -38 3/4

-6.25x > -155/4

Multiply by (-4)

25x > 155

divide by 25,

x > 155/25

x > 31/5

x > 6.2

8 0

2 years ago

101.24 to the nearest hundredth

BaLLatris [955]

Answer:

101.24

Step-by-step explanation:

101.24 is already to the nearest hundredth place.

To the nearest tenth would be 101.2 and to the nearest digit would be 101

5 0

2 years ago