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alexgriva [62]
3 years ago
14

7. Mrs. Everhart developed the theory that all bulldogs are great pets. After all her bulldog Meatball is a

Biology
1 answer:
Leno4ka [110]3 years ago
8 0

Answer:

No it is not a scientific theory.

Explanation:

An explanation of any aspect of the natural phenomenon of the world that can be tested several times and well supported by the evidence, and follows the scientific method. Furthermore known as scientific theory.

Presently, a logical hypothesis must meet a few rules, and one of those is that it must be upheld by a few (and free) strands of proof.  

For this situation, we have just one hypothesis, that bulldogs are great pet and Meatball is great among bulldogs, and it isn't sufficient, at that point it can not be a scientific theory.

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In beans the pod texture and growth form genes are located on different chromosomes. There are two varieties of beans in a farme
irina1246 [14]

Answer:

a. Genotype in F1 - TtBb

   Phenotype in F1 - tough pods, bush-type growth

b. Proportion of F2 that are heterozygous for bush-type growth form = 5/8

c. Proportion of the F2 with tender pods =  1/4

d. Proportion of F2 that are heterozygous for growth form and have tender     pods = 1/8

Explanation:

Since the two traits are located on different chromosomes, they will independently assort during gametes formation. T is dominant over t and B is dominant over b.

Two true-breeding varieties were crossed at the beginning of the program:

TTBB   x   ttbb

All F1 plants will have the genotype TtBb with tough pods and bush-type growth form.

Advancing the cross to F2:

TtBb   x   TtBb

Progeny

1 TTBB   -   tough pods, bush-type

2 TTBb     -  tough pods, bush-type

2 TtBB    -   tough pods, bush-type

4 TtBb     -   tough pods, bush-type

1 TTbb     -    tough pods, climbing-type

2 Ttbb     -    tough pods, climbing-type

1 ttBB       -    tender pods, bush-type

2 ttBb     -      tender pods, bush-type

1 ttbb      -      tender pods, climbing-type

<em>Proportion of F2 that are heterozygous for bush-type growth form = 10/16 = 5/8</em>

<em>Proportion of the F2 with tender pods = 4/16 = 1/4</em>

<em>Proportion of F2 that are heterozygous for growth form and have tender pods = 2/16 = 1/8</em>

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Answer:

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Hope this helps

Explanation:

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Answer:

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Explanation:

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