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Yuki888 [10]
3 years ago
12

What is the answer to - 5y = - 5 and. 7x +6y=7

Mathematics
1 answer:
Vikentia [17]3 years ago
4 0

Answer:

(1/7, 1)

Step-by-step explanation:

By "answer," you probably meant "solution."  What is the "solution of the system of linear equations

- 5y = - 5

+ 7x +6y=7

The first eqation can be solved for y:  y = 1.  Substitute 1 for y in the secon equation.  Then 7x + 6(1) = 7, or 7x = 1, or x = 1/7.

The solution to this system is (1/7, 1)

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Answer:

Step-by-step explanation:

across x axis:(-4,2)

across y-axis:(4,-2)

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The iPhone 6 costs $350 today. If it value depreciates at the rate of 30% per year when will it be
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And its 6 600 and 202 and add 100 which means it will be 12 THATS your answer
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2 years ago
If two thirds of a number is 56, what is three-quarters of that number?
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Answer:

84

Step-by-step explanation:

56/2 = 28

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5 0
3 years ago
A consulting firm has received 2 Super Bowl playoff tickets from one of its clients. To be fair, the firm is randomly selecting
Soloha48 [4]

Answer:

Therefore the only statement that is not true is b.)

Step-by-step explanation:

There employees are 6 secretaries, 5 consultants and 4 partners in the firm.

a.) The probability that a secretary wins in the first draw

= \frac{number \hspace{0.1cm} of \hspace{0.1cm} secreataries}{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} employees}  = \frac{6}{15}

b.) The probability that a secretary wins a ticket on second draw.  It has been given that a ticket was won on the first draw by a consultant.

p(secretary wins on second draw | consultant  wins on first draw)

=\frac{p((consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)\cap( secretary\hspace{0.1cm} wins\hspace{0.1cm} on second \hspace{0.1cm}draw))}{p(consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)}

= \frac{\frac{5}{15}  \times \frac{6}{14}}{\frac{5}{15} }  = \frac{6}{14}  .

The probability that  a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw  = \frac{6}{15} is not true.

The probability that a secretary wins on the second draw  = \frac{number \hspace{0.1cm} of  \hspace{0.1cm} secretaries  \hspace{0.1cm} remaining } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} remaining}  = \frac{6 - 1}{15 - 1}  = \frac{5}{14}

c.) The probability that a consultant wins on the first draw  =

\frac{number \hspace{0.1cm} of  \hspace{0.1cm} consultants  \hspace{0.1cm}  } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} }  = \frac{5 }{15}  = \frac{1}{3}

d.) The probability of two secretaries winning both tickets

= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)

= \frac{6}{15}  \times \frac{5}{14}  = \frac{1}{7}

Therefore the only statement that is not true is b.)

5 0
3 years ago
What is the equation of the line that goes through the points (4,6) and (2,12)?
KengaRu [80]

Answer:

6.72

Step-by-step explanation:

6 0
3 years ago
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