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wariber [46]
3 years ago
15

A confidence interval for the population mean length of hit songs was found to be 4.1 to 5.3 minutes. Find the point estimate (t

hat is, find the midpoint of this confidence interval.)
Mathematics
1 answer:
Zanzabum3 years ago
6 0

Answer:

4.7

Step-by-step explanation:

Given :

initial mean length =4.1  minutes.

Final mean length =5.3 minutes

The mid point of the given interval can be determined by the

Midpoint \ = \frac{Initial\ Mean\ length\ +Final\ Mean\ length }{2}  \\Midpoint \ = \frac{4.1\ +\ 5.3\  }{2}  \\Midpoint \ = \frac{9.4 }{2}  \\Midpoint \ =4.7\\

Therefore 4.7 is the midpoint

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Can someone please help me with this expression?
Anton [14]

the answer to this question is

1220703125


7 0
3 years ago
Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco
Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

d=136

The first part of the trip there was lots of traffic, she only averaged 16 mph;

v_1=16

The second part of the trip there was no traffic so she could drive 44 mph;

v_2=44

She traveled for a total of 5 hours;

t=5

let x represent the time in traffic when she traveled at 16 mph

t_1=x

the time the traffic is clear would be;

t_2=t-t_1=5-x

Recall that distance equals speed multiply by time;

d=v_1t_1_{}_{}^{}+v_2t_2

substituting the values;

136=16x+44(5-x)

solving for x;

\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}

So;

\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

7 0
1 year ago
Please help me! I’ll name you brainiest!!!
Kamila [148]

Answer:

80

Step-by-step explanation:

first, put in (5x-4) for the x in g(x).

g(f(x))=(5x-4)^2 -1

now, FOIL and simplify.

25x^2-40x+16-1

25x^2-40x+15

now, plug in -1 for x.

25(-1)^2-40(-1)+15

25+40+15

80

8 0
3 years ago
Read 2 more answers
Hello! Can some please help me on this problem?
slega [8]

Answer:

It is 1) True hope this helps

5 0
3 years ago
The length of a ribbon is 6/7 meter. Sun Yi needs pieces measuring 1/6 meter for an art project. What is the greatest number of
Strike441 [17]

Answer:

Let's find out!

Step-by-step explanation:

So we have to set up an equation

Let x= # of ribbons that can be cut

Thus:

\frac{1}{6}x =\frac{6}{7} \\x=\frac{6}{7} *\frac{6}{1} \\x=\frac{36}{7}

So, we cannot have 36/7 ribbons! It's not possible!

So we just simplify!

x=5\frac{1}{7}

There we go! She can cut 5 ribbons off!

I'll let you figure out the last one!

Hope this helps!

P.S. Stay Safe!

6 0
2 years ago
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