Considering the figures, the area that will be painted is of 38.9 square feet.
<h3>What is the area of a rectangle?</h3>
The area of a rectangle of length l and width w is given by:
![A = lw](https://tex.z-dn.net/?f=A%20%3D%20lw)
<h3>What is the area of a triangle?</h3>
The area of a triangle of base b and height h is given by:
![A = \frac{bh}{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7Bbh%7D%7B2%7D)
<h3>What is the area of a semi-circle?</h3>
The area of a semi-circle of radius r is given by:
![A = 0.5\pi r^2](https://tex.z-dn.net/?f=A%20%3D%200.5%5Cpi%20r%5E2)
In this problem:
- The rectangle with l = 6 ft and w = 8 ft will be painted, along with the triangle of dimensions b = 8 ft and h = 4 ft.
- The semi-circle with r = 4 ft will not be painted.
Hence, the area that will be painted, in square feet, is given by:
![A = 6 \times 8 + \frac{8(4)}{2} - 0.5\pi 4^2 = 64 - 8\pi = 38.9](https://tex.z-dn.net/?f=A%20%3D%206%20%5Ctimes%208%20%2B%20%5Cfrac%7B8%284%29%7D%7B2%7D%20-%200.5%5Cpi%204%5E2%20%3D%2064%20-%208%5Cpi%20%3D%2038.9)
More can be learned about the area of a figure at brainly.com/question/10489198
The answer is A) -17 very easy question.
To show my work, here.
-17 + (-15) = -32 so that makes the equation true.
Start first by determining the number of books of each category. if x is the nbr. of nonfiction then x+40 is the nbr of fiction. x+x+40=400
so x=180 is the nbr. of nonfiction and 220 is the nbr of fiction.the probability would be 180/400×179/399 so 2nd option
20 x 200 =4000
17 x 193=
3,281
Hope this helped! Mark Brainliest please