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kramer
3 years ago
5

You buy two ads in a newspaper. One ad takes up 58 of a page, and the other ad takes up 18 of a page. How much space did you buy

for ads?
Mathematics
1 answer:
Bas_tet [7]3 years ago
3 0
The answer is 76... I just added the two numbers together
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Adult tickets to a play cost $22. Tickets for children cost $15. Tickets for a group of 11 people cost $228. Write and solve a s
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Answer: 9,2

Step-by-step explanation:

a+c=11

a=11-c

22(11-c) + 15c = 228

242-22c + 15c = 228

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Remember how a + c = 11

a + 2 = 11

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3 years ago
Find dx/dt when y=2 and dy/dt=1, given that x^4=8y^5-240<br><br> dx/dt=
katrin2010 [14]

Answer:

The value of \frac{dx}{dt} is \frac{160}{x^3}.

Step-by-step explanation:

The given equation is

x^4=8y^5-240

We need to find the value of \frac{dx}{dt}.

Differentiate with respect to t.

4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0              [\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]

4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

4x^3\frac{dx}{dt}=40(2)^4(1)

4x^3\frac{dx}{dt}=40(16)(1)

4x^3\frac{dx}{dt}=640

Divide both sides by 4x³.

\frac{dx}{dt}=\frac{640}{4x^3}

\frac{dx}{dt}=\frac{160}{x^3}

Therefore the value of \frac{dx}{dt} is \frac{160}{x^3}.

4 0
3 years ago
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A^2 + B^2 = C^2
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