Question

What is the true solution to the logarithmic equation below? log4[log4(2x]=1

Answer 1

1. 
write 1 as $log_{4}4$ so that we compare same base logarithms:

$log_{4}[{ log_{4}}2x]= log_{4}4$

2. Neglect the equal bases and write the arguments:
 
So ${ log_{4}}2x=4$

repeat step 1, that is write 4 as a logarithm with base 4: 

 $4=4*1=4* log_{4}4= log_{4} 4^{4}$

3. ${ log_{4}}2x=log_{4} 4^{4}$

      $2x=4^{4}$
       
  $x= \frac{4^{4}}{2}= 4^{3}*2=64*2=128$

Answer 2

Answer:

the answer is d on edg.

Step-by-step explanation:

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