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3 years ago

Solve: 2 In 3 = In(x - 4) х = 9 х= 10 x = 13

Mathematics

1 answer:

musickatia [10]3 years ago

7 0

Answer:

5,6and9

Step-by-step explanation:

9-4=5

10-4=6

13-4=9

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Which of the following is equivalent to sec2θ−1sec2θ for all values of θ for which sec2θ−1sec2θ is defined?

galina1969 [7]

Answer:

$2 sin^2 \theta$

Step-by-step explanation:

According to the scenario, the following information is given:

$= \frac{sec^2 \theta - 1 }{sec^2 \theta}$

$= (\frac{1}{\frac{cos^2\theta}{\frac{1}{cos^2\theta} }} - 1)$

$= 1 - cos^2\theta\\\\= 1 - (1 - 2 sin^2 \theta)\\\\= 2 sin^2 \theta$

Therefore for the given equation, the answer is $2 sin^2 \theta$

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3 years ago

The length of a rectangle is 10 yards more than the width. If the perimeter is 68 yards, what are the length and width?

quester [9]

Divide the perimeter by 2, this will give you the sum of one length and one width.

68/2 = 34 yards

Now the length is 10 yards more, so subtract 10 from the 34 and divide by 2 again:

34 - 10 = 24

24 /2 = 12

The width is 12 yards.

The length is 12 + 10 = 22 yards.

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3 years ago

Equivalent Ratios: 300:800 = 30:

Dima020 [189]

Answer:

30:80

Step-by-step explanation:

Because 300 divided by ten is 30 so 800 divided by ten is 80 :)

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2 years ago

Which table represents a linear function?

shusha [124]

Answer:

I believe that the answer is A or the first choice.

Step-by-step explanation:

because the rule for x is +1 and its y is the only one with a rule.

The rule is +1/2

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2 years ago

Determine the shortest segment in △ PQS and △ QRS. Remember that a segment is named by its endpoints (two letters).

irinina [24]

Answer: QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.

Step-by-step explanation:

Since we have given that

ΔPQS, and ΔSQR,

Consider, ΔPQS,

As we know that " the length opposite to the largest angle is the shortest segment."

So, According to the above statement.

$\angle QPS=63\textdegree\\\\\text{So, QS is the shortest segment of this triangle}$

Similarly,

Consider, ΔSQR,

Again applying the above statement, we get that,

$\angle QSR=75\textdegree\\\\\text{ So, QR is the shortest segment of this triangle}$

Hence, QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.

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3 years ago