Question

A spinner is divided into 8 sections of equal size. The sections are numbered 1 through 8.

Answer 1

Answer:

1) 0.125

2) 0.5

3) 0.5

4) 0.125

5) 0.125

Step-by-step explanation:

Taking into account that the spinner is divided in sections of equal size, there is equal probability that the needle land on every of the 8 sections, so the probability that the needle land on section 7 is equal to:

$P=\frac{1}{8}=0.125$

Because, we have 8 possible sections and one of them is section 7.

At the same way, the probability that the needle land on section 9 is:

$P=\frac{1}{8}=0.125$

And the probability that the needle land on section 8 is:

$P=\frac{1}{8}=0.125$

On the other hand, there are 4 section with an even number so, the probability that the needle land on an even numbered section is:

$P=\frac{4}{8}=0.5$

Finally, the probability that the needle land on section 1, 2, 3 or 4 is the sum of the probability that the needle land on section 1, the probability that the needle land on section 2,  the probability that the needle land on section 3 and the probability that the needle land on section 4, so it is equal to:

$P=\frac{1}{8}+\frac{1}{8}+\frac{1}{8}+\frac{1}{8}=\frac{1}{2}=0.5$