Answer:
awww tysm! ill try to help you! :) Step-by-step explanation:
Answer:
2^6 x 3^3 and 12^3
Step-by-step explanation:
First, solve
6^3 x 2^6/2^3
216 x 64/8
13824/8 = 1728
lets solve for the answers
6^3 = 216
Therefore, 6^3 is not an answer
2^6 x 3^3= 64 x 27 = 1728
because both expressions are equal to 1728, this is an answer. this answer can also eliminate 2^3 x 3^3 because it has a lower exponent than the answer that is equal to 1728. therefore, the value of it must be smaller than 1728
12^3 = 1728
This answer is correct, because both values are equal to each other, meaning that 12^6 is larger than 1728
Therefore, your answers will be 2^6 x 3^3 and 12^3
Answer:
<u>1. New York City:</u> The initial charge is $ 2.50 plus $ 0.50 per 1/5 mile when traveling above 12 mph or per 60 seconds in slow traffic or when the vehicle is stopped. There are other surcharges for overnight, rush hour or congestion.
<u>2. Boston:</u> First 1/7 Mile: $2.60 and each 1/7 Mile thereafter: $0.40.
<u>3. Houston:</u> First 1/11 mile $2.80
, each additional 1/11 mile $0.20
. Rate per mile after first mile $2.20 and wait time per minute $0.40.
Step-by-step explanation:
Normally, there's a standard fare for each city, so for answering the question we picked three well-known cities for comparing the fares.
<u>1. New York City:</u> The initial charge is $ 2.50 plus $ 0.50 per 1/5 mile when traveling above 12 mph or per 60 seconds in slow traffic or when the vehicle is stopped. There are other surcharges for overnight, rush hour or congestion.
<u>2. Boston:</u> First 1/7 Mile: $2.60 and each 1/7 Mile thereafter: $0.40.
<u>3. Houston:</u> First 1/11 mile $2.80
, each additional 1/11 mile $0.20
. Rate per mile after first mile $2.20 and wait time per minute $0.40.
<span>h= (-16t^2 + 28t + 7) </span>
find the derivative to get time<span>
<span>
h' = (-32t + 28)
When the ball reaches its maximum height, its
vertical velocity (h’) will be 0 </span></span>
<span>
<span>
0 = -32t + 28 </span></span>
-32t=-28
<span><span>-28/-32 = </span>0.875
seconds </span><span>
<span>
The ball reaches its maximum height in 0.875
seconds after being thrown; plug and chug and:
h= (-16(0.875)^2 + 28(0.875) + 7) = 19.25 feet</span></span>
Max height = 19.25 feet, time = 0.88 seconds
