Electric force is force between 2 charges seperated by distance in space.While gravitational force has to be dependent on the independent action.<span />
Answer:
100.008 km/h
Explanation:
multiply the speed value by 3.6
Answer:
6.04 hr
Explanation:
The bus first travels a distance of 210 km south at an average velocity of 85 km/h. The time, t it takes to cover this distance is gotten from d = vt and t = d/v where d = distance and v = velocity.
So, t = 210 km/85 km/h = 2.47 h
The bus then stops for 25 min. We convert 25 min to hours by dividing by 60.
So 25 min = 25/60 hr = 5/12 h = 0.42 h
The bus then travels 230 km south at an average velocity of 73 km/h.
The time it takes to cover this distance is t = 230 km/73 km/h = 3.15 h
So, the total time for the trip is the sum of each individual time, which is 2.47 h + 0.42 h + 3.15 h = 6.04 hr
So, it takes 6.04 hr for the total trip
Answer:
the speed of the command module relative to Earth just after the separation = 4943.2 Km/hr
Explanation:
Given:
speed of space vehicle =5000 km/hr
rocket motor speed = 71 km/hr relative to the command module
mass of module = m
mass of motor = 4m
By conservation of linear momentum
Pi = Pf
Pi= initial momentum
Pf= final momentum
Since, the motion is only in single direction
Where M is the mass of the space vehicle which equals the sum of motor's mass and the command's mass, Vi its initial velocity, V_mE is velocity of motor relative to Earth, and V_cE is its velocity of the command relative to Earth.
The velocity of motor relative to Earth equals the velocity of motor relative to command plus the velocity of command relative to Earth.
V_mE = V_mc+V_cE
Where V_mc is the velocity of motor relative to command this yields
substituting the values we get
= 4943.2 Km/hr
the speed of the command module relative to Earth just after the separation = 4943.2 Km/hr
Answer:
6.91 Hz
Explanation:
Volume of the cube
= (1.5 x 10⁻² )³m³
= 3.375 x 10⁻⁶ m³
mass of the cube
= 3.375 x 10⁻⁶ x 8920 ( 8.92 g / cm³ = 8920 kg/m³ )
m = 30.105 x 10⁻³ kg
Spring stretches by 2.65 x 10⁻² m due to a force of 1.5 N.
If k be the force constant
k x = F
K x2.65 x 10⁻² = 1.5
k = .566 x 10² N / m
Now frequency of oscillation for spring - mass system is given by
n =
=
n = 6.91 Hz