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3 years ago

Which of the following is a benefit of globalization?

2 answers:

8 0

Globalization connects foreign powers, increases trade, creates new industries, provides jobs, and modernizes countries.

Romashka-Z-Leto [24]3 years ago

7 0

Answer:

Where the answers choices?

Explanation:

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A 1.2 nf parallel-plate capacitor has an air gap between its plates. Its capacitance increases by 3.0 nf when the gap is filled

Damm [24]

Answer:

2.5

Explanation:

The capacitance of a parallel-plate capacitor filled with dielectric is given by

$C=kC_0$

where

k is the dielectric constant

$C_0$ is the capacitance of the capacitor without dielectric

In this problem,

$C_0=1.2 nF$ is the capacitance of the capacitor in air

$C=3.0 nF$ is the capacitance with the dielectric inserted

Solving the equation for k, we find

$k=\frac{C}{C_0}=\frac{3.0 nF}{1.2 nF}=2.5$

3 0

3 years ago

Read 2 more answers

A trick shot archer shoots an arrow with a velocity of 30.0 m/s at an angle of 20.0 degrees with respect to the horizontal. An a

svlad2 [7]

Answer:

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

the apple should be tossed after $\Delta t=0.0173\ s$

Explanation:

Given:

velocity of arrow in projectile, $v=30\ m.s^{-1}$

angle of projectile from the horizontal, $\theta=20^{\circ}$

distance of the point of tossing up of an apple, $d=30\ m$

Now the horizontal component of velocity:

$v_x=v\ cos\ \theta$

$v_x=30\times cos\ 20^{\circ}$

$v_x=28.191\ m.s^{-1}$

The vertical component of the velocity:

$v_y=v.sin\ \theta$

$v_y=30\times sin\ 20^{\circ}$

$v_y=10.261\ m.s^{-1}$

Time taken by the projectile to travel the distance of 30 m:

$t=\frac{d}{v_x}$

$t=\frac{30}{28.191}$

$t=1.0642\ s$

Vertical position of the projectile at this time:

$h=v_y.t-\frac{1}{2}g.t^2$

$h=10.261\times 1.0642-\frac{1}{2} \times 9.8\times 1.0642^2$

$h=5.3701\ m$

Now this height should be the maximum height of the tossed apple where its velocity becomes zero.

$v'^2=u'^2-2g.h$

$0^2=u'^2-2\times 9.8\times 5.3701$

$u'=10.259\ m.s^{-1}$ is the initial velocity of tossing the apple.

Time taken to reach this height:

$v'=u'-g.t'$

$0=10.259-9.8\times t'$

$t'=1.0469\ s$

We observe that $t>t'$ hence the time after the launch of the projectile after which the apple should be tossed is:

$\Delta t=t-t'$

$\Delta t=1.0642-1.0469$

$\Delta t=0.0173\ s$

8 0

3 years ago

Consider Compton Scattering with visible light.A photon with wavelength 500nm scatters backward(theta=180degree) from a free ele

JulijaS [17]

Answer: $4.86(10)^{-12}m$

Explanation:

The Compton Shift $\Delta \lambda$ in wavelength when photons are scattered is given by the following equation:

$\Delta \lambda=\lambda' - \lambda_{o}=\lambda_{c}(1-cos\theta)$ (1)

Where:

$\lambda'=500 nm=500(10)^{-9} m$ is the wavelength of the scattered photon

$\lambda_{o}$ is the wavelength of the incident photon

$\lambda_{c}=2.43(10)^{-12} m$ is a constant whose value is given by $\frac{h}{m_{e}.c}$ , being $h=4.136(10)^{-15}eV.s$ the Planck constant, $m_{e}$ the mass of the electron and $c=3(10)^{8}m/s$ the speed of light in vacuum.

$\theta=180\°$ the angle between incident phhoton and the scatered photon.

$\Delta \lambda=2.43(10)^{-12} m (1-cos(180\°))$ (2)

$\Delta \lambda=4.86(10)^{-12}m$ (3) This is the shift in wavelength

5 0

3 years ago

To make 2 molecules of water, you need 2 molecules of hydrogen plus 1 molecule of oxygen. If I have unlimited amounts of oxygen

Semenov [28]

Hey there,

So first we need to know how much molecules are there in 4 grams of hydrogen right?
In one gram of hydrogen there are 6.0221415 multiplied by 10^25 molecules right?(this number is known as avagadors constant )

And to make one molecule of water u need two molecules of hydrogen and one of oxygen.
And oxygen is unlimited right?

So when we have 6.0221415 grams of hydrogen tow if these are required to make one water.
So divide that by two and you get 3.0110704 multiplied by 10^25.
So the answer is you can make the above number of water molecules.

Hope this helps!!!

5 0

3 years ago

A train of mass 50000 kg starts from rest and moves with uniform acceleration 5 km/h2 then, find its kinetic energy after 30 min

r-ruslan [8.4K]

Answer:

12 kJ

Explanation:

Given:

v₀ = 0 km/h

a = 5 km/h²

t = 30 min = 0.5 h

Find: v

v = at + v₀

v = (5 km/h²) (0.5 h) + 0 km/h

v = 2.5 km/h

v = 2.5 km/h × (1000 m/km) × (1 h / 3600 s)

v = 0.694 m/s

KE = ½ mv²

KE = ½ (50,000 kg) (0.694 m/s)²

KE = 12,000 J

KE = 12 kJ

7 0

3 years ago