Question

The fuction f(z)=}{sin(z)}" alt="\frac{cos(z)}{sin(z)}" align="absmiddle" class="latex-formula"> is conformal at

Answer 1

Answer:

Step-by-step explanation:

The function f(z) is conformal at z0 if there is an angle φ and a scale a > 0 such that for any smooth curve γ(t) through z0 the map f rotates the tangent vector at z0 by φ and scales it by a. That is, for any γ, the tangent vector (f ◦ γ)/(t0) is found by rotating γ/(t0) by φ and scaling it by a.