Answer:
36 meters
Step-by-step explanation:
9 divided by 3 is 3
That means for every 1 meters is 6 meters shadow wise because 3 meters equal to .5 meters.
6 meters of the pole times 6 meters per one real meter equals 36 shadow meters.
Hope that helped, if it did please give me the brainliest.
A linear equation of the form :
y = mx+b
can have at the most ONE x-intercept and at the most ONE y-intercept
I can conclude that this linear equation DOESN'T pass through the origin (O) and that it intercepts the x-axis as well as the y-axis
Answer:
598 meters
Step-by-step explanation:
In the problem, the word 'decend' means to decrease in elevation.
<u>Our equation:</u>
<u>
</u>
<u>Add</u><u> </u><u>153</u><u> </u><u>to</u><u> </u><u>both</u><u> </u><u>sides</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>equation</u><u>:</u>

598 meters represents the original height of the helicopter.
Answer:
15°.
Step-by-step explanation:
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Have a good Day!