The slope of the line is positive
250 lunches are produced by the small business in last week.
<u>Step-by-step explanation:</u>
It is given that,
- y ⇒ the average cost per week.
- x ⇒ the number of lunches produced per week.
The function relating these two factors x and y is given as y = 2.1x + 75
- The cost of the last week is y = $600.
- The lunches made last week is x = unknown.
<u>To find the value of x :</u>
Substitute y= 600 in the given function,
⇒ 600 = 2.1x + 75
⇒ 2.1x = 600 - 75
⇒ x = 525 / 2.1
⇒ x = 250
Therefore, the lunches prepared last week is 250.
7 + 2x - 6 = -3x - 3 - 4
2x + 1 = -3x - 3 - 4
2x + 1 = -3x - 7
2x + 1 + 3x = -7
5x + 1 = -7
5x = -7 - 1
5x = -8
x = -8/5.
Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
For lines to be perpendicular, their slopes have to be the negative reciprocal of each other. (Basically flip the sign +/- and the fraction(switch the numerator and the denominator))
For example:
Slope = 2 or 
Perpendicular line's slope =
(flip the sign from + to -, and flip the fraction)
Slope = 
Perpendicular line's slope =
(flip the sign from - to +, and flip the fraction)
y = 1/3x + 4 The slope is 1/3, so the perpendicular line's slope is
or -3.
Now that you know the slope, substitute/plug it into the equation:
y = mx + b
y = -3x + b To find b, plug in the point (1, 2) into the equation, then isolate/get the variable "b" by itself
2= -3(1) + b Add 3 on both sides to get "b" by itself
2 + 3 = -3 + 3 + b
5 = b
y = -3x + 5