Solve fro the Equation below:<br><br> 7+2(x-3)=-3(x+1)-4

In a normal distribution, what is the probability that a data value will fall below the

Serga [27]

Answer:

A 99.96%

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is positive if the raw score is above the mean while the z score is negative if the raw score is below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma} \\\\where\ z=z-score,\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation\\\\For\ a\ sample\ size(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }$

The probability can be gotten from the normal distribution table. Therefore from the normal table:

P(z < 3.37) = 0.9996 = 99.96%

8 0

2 years ago

Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

4 0

3 years ago

Please help me solve this!!

Brut [27]

Answer:

30

by-step explanation:

5*5=30

3 0

3 years ago

Which is best estimate of the circumference of this circle when radius is 3

nydimaria [60]

Answer:

D/About 18.85

Step-by-step explanation:

So, Using the Circle Circumfrince Formula:

$A=2\pi r\\A=6\pi \\A=18.85....$

There you go!

Hope this helps!

P.S. Stay Safe!

4 0

3 years ago

Please help me i been stuck all day on this. Find the value of x.

erastova [34]

Answer:

14

Step-by-step explanation:

105 and (6x-21) the same. So you do 105 minus 21, then divide that by 6.

7 0

3 years ago

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Solve fro the Equation below: 7+2(x-3)=-3(x+1)-4