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rjkz [21]
4 years ago
11

You have a small business making and delivering box lunches. You calculate your average weekly cost y of producing x lunches usi

ng the function y = 2.1x + 75. Last week your cost was $600. How many lunches did you make last week?
Mathematics
1 answer:
kogti [31]4 years ago
6 0

250 lunches are produced by the small business in last week.

<u>Step-by-step explanation:</u>

It is given that,

  • y ⇒ the average cost per week.
  • x ⇒ the number of lunches produced per week.

The function relating these two factors x and y is given as y = 2.1x + 75

  • The cost of the last week is y = $600.
  • The lunches made last week is x = unknown.

<u>To find the value of x :</u>

Substitute y= 600 in the given function,

⇒ 600 = 2.1x + 75

⇒ 2.1x = 600 - 75

⇒ x = 525 / 2.1

⇒ x = 250

Therefore, the lunches prepared last week is 250.

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The weight of water is 62 1/2 per cubic feet. Water that weighs 325 lbs will fill how many cubic feet
yulyashka [42]

Water that weighs 325 lbs will fill 5.2 cubic feet.

Step-by-step explanation:

This is a simple question of cross multiplication

<u>DATA:</u>

<em>1. The weight of water for 1 cubic feet is 62.5</em>

<em>2. The weight of water for 'X' cubic feet is 325 </em>

<em>3. To find x, form an equation:</em>

Cubic feet : Weight of water

     1           :         62.5

     X           :         325

<em>4. Cross multiply</em>

X x 62.5 = 1 x 325

62.5X = 325

<em>5. Make X the subject</em>

X = \frac{325}{62.5}

<em>6. Solve to find X</em>

X = 5.2 cubic feet

Therefore, water that weighs 325 lbs will fill 5.2 cubic feet.

Key words: Conversion

Learn more about conversions at

  • brainly.com/question/1548911
  • brainly.com/question/555814
  • brainly.com/question/4837736

#LearnwithBrainly

4 0
4 years ago
What is twenty times negative fifteen
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Answer:

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Step-by-step explanation:

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Divide the following polynomial using synthetic division, then place the answer in the proper location on the grid. Write answer
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Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)
ELEN [110]

Question:

Find the point (,) on the curve y = \sqrt x that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})

Step-by-step explanation:

y = \sqrt x can be represented as: (x,y)

Substitute \sqrt x for y

(x,y) = (x,\sqrt x)

So, next:

Calculate the distance between (x,\sqrt x) and (3,0)

Distance is calculated as:

d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}

So:

d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}

d = \sqrt{(x-3)^2 + (\sqrt x)^2}

Evaluate all exponents

d = \sqrt{x^2 - 6x +9 + x}

Rewrite as:

d = \sqrt{x^2 + x- 6x +9 }

d = \sqrt{x^2 - 5x +9 }

Differentiate using chain rule:

Let

u = x^2 - 5x +9

\frac{du}{dx} = 2x - 5

So:

d = \sqrt u

d = u^\frac{1}{2}

\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}

Chain Rule:

d' = \frac{du}{dx} * \frac{dd}{du}

d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}

d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}

d' = \frac{2x - 5}{2\sqrt u}

Substitute: u = x^2 - 5x +9

d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}

Next, is to minimize (by equating d' to 0)

\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0

Cross Multiply

2x - 5 = 0

Solve for x

2x  =5

x = \frac{5}{2}

Substitute x = \frac{5}{2} in y = \sqrt x

y = \sqrt{\frac{5}{2}}

Split

y = \frac{\sqrt 5}{\sqrt 2}

Rationalize

y = \frac{\sqrt 5}{\sqrt 2} *  \frac{\sqrt 2}{\sqrt 2}

y = \frac{\sqrt {10}}{\sqrt 4}

y = \frac{\sqrt {10}}{2}

Hence:

(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})

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