Let x be the first digit.
Let y be the second digit.
Let z be the third digit.
x+y+z=18
y= (-2)(-4)
y= 8
x= 3^2
x= 9
Therefore z=1.
The number is
= 100x+10y+z
= 100(9)+10(8)+(1)
= 981
the K is next to the find like
Answer:
A & D
Step-by-step explanation:
The parabola opens up, so the minimum value of y is at the point (1, -2) and the graph passes thru the x-axis at 3 and -1, so those are the x-intercepts.
The axis of symmetry is x = 1, not y = -2 and the graph never has a maximum value. Parabolas that open up never have a maximum value.
<h3>
Answer:</h3>
A. 3x² +6
<h3>
Explanation:</h3>
(f-g)(x) = f(x) -g(x) = (4x²+1) -(x²-5) . . . . . substitute the function definitions
... = 4x² +1 -x² +5 . . . . . . . . . . . eliminate parentheses
... = (4-1)x² +(1+5) . . . . . . . . . . . collect like terms
... = 3x² +6
(2x + 10)(x - 9)
2x(x - 9) + 10(x - 9)
2x(x) - 2x(9) + 10(x) - 10(9)
2x² - 18x + 10x - 90
2x² - 8x - 90
