Answer:
The number of miles at which a car rented from either company cost the same amount is <u>50 miles</u>.
Step-by-step explanation:
Let x represents the number of miles at which a car rented from either company cost the same amount. Therefore, we can have the following equation:
RC = 25 + 0.14x ....................... (1)
BC = 23 + 0.18x ...................... (2)
Where;
RC = Total cost of Rent-Me Rent-A-Car
BC = Total cost of Better Deal Rental Car
The the cost of the two companies equal where RC = BC. Therefore, we equate equations (1) and (2) and solve for x as follows:
25 + 0.14x = 23 + 0.18x
25 - 23 = 0.18x - 0.14x
2 = 0.04x
x = 2 / 0.04
x = 50
Therefore, the number of miles at which a car rented from either company cost the same amount is <u>50 miles</u>.
<u>Note:</u>
This can be confirmed for equations (1) and (2) individually by substituting for x = 50 as follows:
For equation (1):
RC = 25 + 0.14(50)
RC = 25 + 7
RC = 32
For equation (2):
BC = 23 + 0.18(50)
BC = 23 + 9
BC = 32
Therefore, RC = BC = 32 confirms the answer.
Find the greatest common factor and then divide each number by it.
in this case the gcf for 75 and 100 is 25.
75 divided by 25 = 3
100 divided by 25 = 4
so 75/100 simplified = 3/4
The tank is NOT filled with 8314.5 L of a liquid. I guess you meant <span>The tank is completely filled with 8314.5 grams of liquid." </span>
<span>(8314.5 g) / (230 L) = 36.15 g/L . Hope this helps!</span>
No.
The distance is |-5 -3| = 8 units. (Y-coordinates are the same, so the distance is measured entirely in the x-direction. Distance is non-negative.)
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)
Multiply equation (1) by 2:
22x + 30y + 46 = 0
Multiply equation (2) by 15:
105x - 30y - 300 = 0
Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]
Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3
Therefore, x = 2 and y = -3.