Answer:
I don't think the answer exist
Step-by-step explanation:
for y=6x
when y=0, x=0 and when x=0, y=0
hence, (x,y)=(0,0)
for y=x+6
when y=0, x+6=0, x=-6 and when x=0, y=6
hence (x,y) = (-6,6)
for y=x^2+6
when x=0, y=6 and when y=0,
x^2+6=0
subtracting 6 from both sides
x^2=-6
take the square root of both sides and get
x=+ or -sqrt(-6)= + or - (2.45i)
i.e. x=+2.45i or x=-2.45i these are complex roots anyway, and its out of point.
for y=2x+6
when x=0, y=6 and when y=0,
2x+6=0,
2x=-6,
x=-3
the coordinates give (x,y)=(-3,6)
conclude....
