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Lostsunrise [7]
3 years ago
15

The scatter plot below represents the number of runners in a famous city race. The years are tracked beginning in 2001 estimate

the equation for the line of best fit

Mathematics
1 answer:
Helga [31]3 years ago
7 0
2-69+2=69 420 ya digggggggggg
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An orange is shot up into the air with a catapult. The function h given by
Mrrafil [7]

Answer:

Velocity = 59 feet/second

Step-by-step explanation:

h(t) = 15 + 60t – 16t2

Time t = 1 second

Let's substitute time into the equation to get the distance

h(t) = 15+60(1)-16(1)²

h(t) = 15 + 60 - 16

h(t) = 59 feet

Speed or velocity = distance/time

Distance = 59 feet

Time = 1 second

Velocity = 59/1

Velocity = 59 feet/s

7 0
3 years ago
50 POINTS ANSWER QUICK
Andreyy89

Answer:

part a= -1

part b= -4

Step-by-step explanation:

f(x) is y. plug in -4 for y and check x

6 0
3 years ago
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Suppose you work for a company that purchases lumber from a major supplier and delivers this lumber to individual clients. Suppo
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3 years ago
g On any day, the probability of rain is 0.3. The occurrence of rain on any day is independent of the occurrence of rain on any
Ksju [112]

Answer:

0.249579

Step-by-step explanation:

P(rain) = 0.3

P(no rain) = 1 - 0.3 = 0.7

The event of rain falling a second time within the next 5 days is possible in these ways

1. Rain on days 1 and 2

2. Rain on days 1 and 3; none on day 2

3. Rain on days 1 and 4; none on days 2 and 3

4. Rain on days 1 and 5; none on days 2, 3 and 4

5. Rain on days 1 and 6; none on day 2, 3, 4 and 5

P(\text{second rain within 5 days}) = 0.3^2+0.3^2\times0.7+0.3^2\times0.7^2+0.3^2\times0.7^3+0.3^2\times0.7^4 = 0.3^2(1+0.7+0.7^2+0.7^3+0.7^4)= 0.09\times2.7731=0.249579

5 0
4 years ago
Find the midpoint of PQ<br><br> P(4 1/3, 3 1/6), Q(-2 1/5, 3 2/3)
Paha777 [63]

Answer:

(1\frac{1}{15},3\frac{5}{12})

Step-by-step explanation:

To find the midpoint, you must average the x's then average the y's.

So the x's are 4 \frac{1}{3} and -2\frac{1}{5}.

The y's are 3\frac{1}{6} and 3\frac{2}{3}.

To find an average of a data with 2 elements you must add the two elements then take that sum and divide it by 2.

So this is what we will do with the x's then the y's.

So first x:

\frac{4\frac{1}{3}+-2\frac{1}{5}}{2}

Write as improper fractions:

\frac{\frac{13}{3}+\frac{-11}{5}}{2}

Division by 2 is the same as multiplying by 1/2:

\frac{13}{6}+\frac{-11}{10}

The least common multiple of 6 and 10 is 30.  We will multiply first fraction by 5/5 and 3/3 for the second so we can have the same denominator.

\frac{65}{30}+\frac{-33}{30}

Now that the bottoms are the same we can write as one fraction:

\frac{65+-33}{30}

Simplify:

\frac{32}{30}

If you want the answer as a mix fraction like your question began as we can do that by first figuring out how many 30's are in 32 and what is the remainder of that division.

There is one 30 and 32 and so 32-30=2 is the remainder.

1\frac{2}{30}

Reduce by dividing top and bottom by 2:

1\frac{1}{15}

Now for y:

\frac{3\frac{1}{6}+3\frac{2}{3}}{2}

Write the mix fractions as improper fractions:

\frac{\frac{19}{6}+\frac{11}{3}}{2}

Dividing by 2 is the same as multiplying by 1/2:

\frac{19}{12}+\frac{11}{6}

The least common multiple of 12 and 6 is 12 so I'm going to multiply the second fraction by 2/2 so the denominators will be the same:

\frac{19}{12}+\frac{22}{12}

Since the denominators are the same we can write as a single fraction:

\frac{41}{12}

How many 12's are in 41? 3 and so the remainder is 41-3(12)=41-36=5.

3\frac{5}{12}

So the midpoint is:

(1\frac{1}{15},3\frac{5}{12}).

6 0
3 years ago
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