Need help trying to solve this equation 23+(2x-1)>x

1 answer:

7 0

<u><em>x>-22 is the correct answer. </em></u> First you had to used their group like terms, and it gave us, $2x+23-1>x$ . Then add and subtract by the numbers, and it gave us, $2x+22>x$ . You can also subtract by 22 from both sides of equation, and it gave us, $2x+22-22>x-22$ . Simplify, and it gave us, $2x>x-22$ . Subtract by x from both sides of equation, and it gave us, $2x-x>x-22-x$ . And finally simplify, and it gave us the answer is x>-22 is the correct answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

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Last Sunday a certain store sold copies of 256 Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the stor

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Answer:

D. $\frac{400p}{500-p}$

Step-by-step explanation:

let's call A the number of copies sold of newspaper A and B the number of copies sold of newspaper B.

So, we can formulate the following equations from the sentence: a certain store sold copies of 256 Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each as:

A + B = 256 (1)

1A + 1.25 B = Total Revenue (2)

Then, r and p are equal to:

$r=\frac{A}{Total Revenue}*100=\frac{100A}{A+1.25B}$ (3)

$p=\frac{A}{256} *100=\frac{100A}{256}$ (4)

Isolating A from (4) and B from (1), we get:

$A=\frac{256p}{100} =2.56p$ (5)

$B=256-A=256-2.56p$ (6)

Finally, replacing (5) and (6) in (3), we get:

$r=\frac{100A}{A+1.25B}=\frac{100(2.56p)}{2.56p+1.25(256-2.56p)}\\\\r=\frac{256p}{2.56p+320-3.2p}=\frac{256p}{320-0.64p}\\\\r=\frac{256p/0.64}{(320-0.64p)/0.64}=\frac{400p}{500-p}$