All categories

4 years ago

Need help trying to solve this equation 23+(2x-1)>x

1 answer:

7 0

x>-22 is the correct answer. First you had to used their group like terms, and it gave us, $2x+23-1>x$ . Then add and subtract by the numbers, and it gave us, $2x+22>x$ . You can also subtract by 22 from both sides of equation, and it gave us, $2x+22-22>x-22$ . Simplify, and it gave us, $2x>x-22$ . Subtract by x from both sides of equation, and it gave us, $2x-x>x-22-x$ . And finally simplify, and it gave us the answer is x>-22 is the correct answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

You might be interested in

What is the function rule for the line?

Papessa [141]

Answer:

A (Wrong)

B (Correct)

C (Wrong)

D (Wrong)

Step-by-step explanation:

The y-intercept is $-2$ because the line intercepts are touch the y-intercept at $-2$ . Further more find two point on the line that has whole number in the order pair. Which is $-\frac{3}{2}$ meaning that it takes the point to move $3$ units down and to $2$ right.

7 0

3 years ago

Write down the integer values satisfied by the diagram

____ [38]

Answer:

{0, 1, 2, 3}

Step-by-step explanation:

The diagram includes the interval:

(-1, 3]

The integer values in the given interval are:

{0, 1, 2, 3}

3 0

3 years ago

Read 2 more answers

In one serving of trail mix, the ratio of the number of ounces of raisins to the number of

lakkis [162]

Answer:

Step-by-step explanation:

i hope this helps can you give brainlylist.

8 0

3 years ago

I need help with #1 of this problem. It has writings on it because I just looked up the answer because I’m confused but I want t

belka [17]

In the figure below

1) Using the theorem of similar triangles (ΔBXY and ΔBAC),

$\frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC}$

Where

$\begin{gathered} BX=4 \\ BA=5 \\ BY=6 \\ BC\text{ = x} \end{gathered}$

Thus,

$\begin{gathered} \frac{4}{5}=\frac{6}{x} \\ \text{cross}-\text{multiply} \\ 4\times x=6\times5 \\ 4x=30 \\ \text{divide both sides by the coefficient of x, which is 4} \\ \text{thus,} \\ \frac{4x}{4}=\frac{30}{4} \\ x=7.5 \end{gathered}$

thus, BC = 7.5

2) BX = 9, BA = 15, BY = 15, YC = y

In the above diagram,

$\begin{gathered} BC=BY+YC \\ \Rightarrow BC=15\text{ + y} \end{gathered}$

Thus, from the theorem of similar triangles,

$\begin{gathered} \frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC} \\ \frac{9}{15}=\frac{15}{15+y} \end{gathered}$

solving for y, we have

$\begin{gathered} \frac{9}{15}=\frac{15}{15+y} \\ \text{cross}-\text{multiply} \\ 9(15+y)=15(15) \\ \text{open brackets} \\ 135+9y=225 \\ \text{collect like terms} \\ 9y\text{ = 225}-135 \\ 9y=90 \\ \text{divide both sides by the coefficient of y, which is 9} \\ \text{thus,} \\ \frac{9y}{9}=\frac{90}{9} \\ \Rightarrow y=10 \end{gathered}$

thus, YC = 10.

4 0

1 year ago

Expand (a+b)^7 using pascal triangle

Inga [223]

(a+b)^7= a^7+ 7a^7b+ 21 a^6b²+ 35a^5b³+ 35 a⁴b⁴+ 21 a³b^5 + 7a²b^6 + b^7

8 0

3 years ago