4 years ago

Solve x2 – 8x 41 = 0 for x. x = –4 ± 5i x = 4 ± 5i

1 answer:

3 0

X^2 - 8x + 41 = 0
$x = \frac{-(-8)\pm\sqrt{(-8)^2-(4\times41)}}{2}=\frac{8\pm\sqrt{64-164}}{2}\\=\frac{8\pm\sqrt{-100}}{2}=\frac{8\pm10i}{2}=4\pm5i$

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