Answer:
1. 4
2. 9
3. <
Step-by-step explanation:
The ratio 4 to 5 means that the left model should have 4 segments shaded (out of 5 given).
The ratio 9 to 10 means that the right model should have 9 segments shaded (out of 10 given).
Compare the shaded regions. If you draw the horizontal line in the left model. then there will be 8 segments shaded (out of 10), this means the ratio 4 : 5 is less than the ratio 9 : 10.
Radius =
<span>
<span>
<span>
23.125
</span>
</span>
</span>
cm
Cylinder Volume = <span>π <span>• r² • height
</span></span>
Cylinder Volume = 3.14 * 23.125^2 * 18.5
Cylinder Volume =
<span>
<span>
<span>
31,064.53515625
</span>
</span>
</span>
Cylinder Volume =
<span>
<span>
<span>
31,064.54 cubic centimeters
</span></span></span>
<span>A jeweler buys a ring from an artisan for 85$. He sells the ring at his store at 135% increase in price. What is the retail price? PLEASE SHOW UR WORK!!!
1.35(</span><em>135%</em><span>) x 85( <em>the price it was bought for</em>)
= $114.75
</span>
If you divide by 8, you can put the equation into intercept form. That form is ...
... x/a + y/b = 1
where <em>a</em> and <em>b</em> are the x- and y-intercepts, respectively.
Here, your equation would be
... x/(-2) + y/(-4) = 0
The graph with those intercepts is not shown with your problem statement here. See the attachment for the graph.
Answer:
Step-by-step explanation:
Part 1:
Let
Q₁ = Amount of the drug in the body after the first dose.
Q₂ = 250 mg
As we know that after 12 hours about 4% of the drug is still present in the body.
For Q₂,
we get:
Q₂ = 4% of Q₁ + 250
= (0.04 × 250) + 250
= 10 + 250
= 260 mg
Therefore, after the second dose, 260 mg of the drug is present in the body.
Now, for Q₃ :
We get;
Q₃ = 4% of Q2 + 250
= 0.04 × 260 + 250
= 10.4 + 250
= 260.4
For Q₄,
We get;
Q₄ = 4% of Q₃ + 250
= 0.04 × 260.4 + 250
= 10.416 + 250
= 260.416
Part 2:
To find out how large that amount is, we have to find Q₄₀.
Using the similar pattern
for Q₄₀,
We get;
Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹
Taking 250 as common;
Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)
= 2501 − 0.04401 − 0.04
Q₄₀ = 260.4167
Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.
Part 3:
From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.
