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natita [175]
3 years ago
9

Which expression is equivalent to log_5(x/4)^2?

Mathematics
1 answer:
viktelen [127]3 years ago
3 0

For this case we must find an expression equivalent to:

log_ {5} (\frac {x} {4}) ^ 2

So:

We expanded log_ {5} ((\frac {x} {4}) ^ 2)by moving 2 out of the logarithm:

2log_ {5} (\frac {x} {4})

By definition of logarithm properties we have to:

The logarithm of a product is equal to the sum of the logarithms of each factor:

log (xy) = log (x) + log (y)

The logarithm of a division is equal to the difference of logarithms of the numerator and denominator.

log (\frac {x} {y}) = log (x) -log (y)

Then, rewriting the expression:

2 (log_ {5} (x) -log_ {5} (4))

We apply distributive property:

2log_ {5} (x) -2log_ {5} (4)

Answer:

An equivalent expression is:

2log_ {5} (x) -2log_ {5} (4)

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Write the following proportion:<br> 8 is to 64 as 2 is to X
Andrews [41]
1 way
\frac{8}{64}  =  \frac{2}{x}  \\  \\ &#10; \frac{8:4}{64:4}  =  \frac{2}{x}  \\  \\ &#10; \frac{2}{16}  =  \frac{2}{x}    ⇔  x = 16
......................................................
2.way
\frac{8}{64}  =  \frac{2}{x}
<span>We multiply the cross
</span>
8x = 2 * 64&#10;8x = 128&#10;x = 16
3 0
3 years ago
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Help 10 points!!
Trava [24]
The answer would be c/8
8 0
3 years ago
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Plz help me get the answer ASAP
lakkis [162]

solve the inequality:

1/2c>-1

divide 1/2 from both sides

c>-2 is the answer

6 0
4 years ago
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The ratio of the perimeters of two rectangles is 4 to 7. The perimeter of the larger rectangle is 42 inches. What is the perimet
Lelu [443]

P = 42(4/7)

p = (42)(4)/(1)(7)

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Answer : D , 24 inches


I hope that's help !


6 0
4 years ago
How to solve number 44
solniwko [45]
OK. 

Let's say a member and a non member each visit the garden ' V ' times.

The non-member's cost for each visit is  $6 .
The non member's cost for ' V ' visits is  6 V .
His total cost for the year is  6 V .

The member's cost for each visit is $3.
The member's cost for ' V ' visits is  3V .
His total cost for the year is  3V  +  the  $24 to join.

We want to know what ' V ' is  (how many times each one can visit)
if their total costs are the same.

So let's just write an equation that SAYS their costs are the same,
and see what ' V ' turns out to be.

             Non-member's cost for the year =  Member's cost for the year

                                                            6 V  =  3 V + 24

Subtract  3V  from each side:          3 V  =            24

Divide each side by  3 :                       V  =              8  .

-- If they both visit the garden 1, 2, 3, 4, 5, 6, or 7 times in the year,
the member will spend MORE than the non member.

-- If they both visit the garden 8 times in the year,
they'll both spend the same amount.  ($48)

-- If they both visit the garden MORE than 8 times in the year,
the member will spend LESS than the non-member.
______________________________________________ 

That was the algebra way to do it.

Now here is the cheap, sleazy, logical, easy way to do it:

The non-member spends (6 - 3) = $3 MORE than the member for each visit ?

After how many visits does the $3 more each time add up to the $24 that
it cost the member to join for the year ?

           $24 / $3  =  8 visits  .
5 0
4 years ago
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