At point of intersection the two equations are equal,
hence, 6x³ =6x²
6x³-6x²=0
6x²(x-1)=0 , the values of x are 0 and 1
The points of intersection are therefore, (0,0) and (1,6)
To find the slopes of the tangents at the points of intersection we find dy/dx
for curve 1, dy/dx=12x, and the other curve dy/dx=18x²
At x=0, dy/dx=12x =0, dy/dx=18x² = 0, hence the angle between the tangents is 0, because the tangents to the two curves have the same slope which is 0 and pass the same point (0,0) origin.
At x=1, dy/dx =12x = 12, dy/dx= 18x² =18, Hence the angle between the two tangents will be given by arctan 18 -arctan 12
= 86.8202 - 85.2364 ≈ 1.5838, because the slope of the lines is equal to tan α where α is the angle of inclination of the line.
Hmmmm...... Are you a 6th grader? I remember doing these in 6th grade.
Ok so find 1's
remember that 4/4=1 also x/x=1 those are ones
also remember
if you had
10/30 that equals 10/10 times 1/3=1 times 1/3
so find ones
4/10=2/2 times 2/5=1 times 2/5=2/5
Answer:
the answer is -97, -83, -21, 34, 55, 56
Step-by-step explanation:
The simple way to put it is negitives are backwards, the bigger the number the lesser it gets. So always put the highest negitive as least, hope this helps!
10% as a decimal would be .10
