we gonna need a little more than that to help ya, bud.
Answer:
Two geometrical shapes which are identical in shape and size are said to be congruent. We use the symbol '≅' to denote congruence.
Step-by-step explanation:
Answer:
when you divide you get -11/12
if you have a calculator you could add the 5/8 and 3/4
then add the -2/3 and the -5/6
then divide the first answer by the second answer
Answer:
The inverse will be:
![y' = \frac{\sqrt{x+4}}{3}](https://tex.z-dn.net/?f=y%27%20%3D%20%5Cfrac%7B%5Csqrt%7Bx%2B4%7D%7D%7B3%7D)
Step-by-step explanation:
In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :
![f(x) = 9x^{2} - 4](https://tex.z-dn.net/?f=f%28x%29%20%20%3D%209x%5E%7B2%7D%20-%204)
![y = 9x^{2} - 4](https://tex.z-dn.net/?f=y%20%3D%209x%5E%7B2%7D%20-%204)
![x = 9y' ^{2} - 4](https://tex.z-dn.net/?f=x%20%3D%209y%27%20%5E%7B2%7D%20-%204)
Now solve for y'.
First add 4 in both sides of the equation and change to the left y'.
![x + 4= 9y'^{2} - 4+4](https://tex.z-dn.net/?f=x%20%2B%204%3D%209y%27%5E%7B2%7D%20-%204%2B4)
= x + 4
Second divide by 9
/9 = (x + 4)/9
= (x + 4)/9
Now you will have to clear y, with the square root.
[/tex] =
Simplifying terms
![y' = \frac{\sqrt{x+4}}{3}](https://tex.z-dn.net/?f=y%27%20%3D%20%5Cfrac%7B%5Csqrt%7Bx%2B4%7D%7D%7B3%7D)
![f^{-1}(x) = \frac{\sqrt{x+4}}{3}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%20%3D%20%5Cfrac%7B%5Csqrt%7Bx%2B4%7D%7D%7B3%7D)
You can check the answer by doing the evaluation of the following equation:
(f o
) (x)
substitute the equation for y' or inverse function ![f^{-1}](https://tex.z-dn.net/?f=f%5E%7B-1%7D)
f(
)
Now substitue the value into f(x)
You will have
![= 9(\frac{\sqrt{x+4} }{3}} )^{2} - 4\\\\Solving\\\\9(\frac{{x+4} }{9}} ) - 4](https://tex.z-dn.net/?f=%3D%209%28%5Cfrac%7B%5Csqrt%7Bx%2B4%7D%20%7D%7B3%7D%7D%20%29%5E%7B2%7D%20%20-%204%5C%5C%5C%5CSolving%5C%5C%5C%5C9%28%5Cfrac%7B%7Bx%2B4%7D%20%7D%7B9%7D%7D%20%29%20%20-%204)
=x