B = 2 + 2H
A = 20 ft^2
H = H
Since the Area of a Triangle is Base * Height then the formula should be:
A = BH
20 = H(2+2H)
20 = 2H^2 + 2H
0 = 2H^2 + 2H - 20
Find the zeros of the quadratic equation through substituting the values of a,b, and c. You will get the zeros of x = 2.7 and -3.7. The only thing that would make sense is you use the x=2.7 because there are no negative heights.
Since b = 2h+2
b= 2(2.7) + 2
b= 5.4 + 2
b=7.4
I don't know where you got 4 and 10, but what I got is different.
Answer:
18 children weighed less than 50 pounds.
Step-by-step explanation:
Ok, adding into the explanation what the heck this kind of a table is. The "stem" column is the tens place of each of the children's weights. The "leaf" is the ones digit of each of the children's weights. So in the row where the stem is 2, there were 2 kids weighing 23 and 25 pounds.
For your question, we have to add up how many students have a weight with a "stem" less than 5, because that's where 50 pounds starts.
8 + 2 + 5 + 3 = 18 children weighed less than 50 pounds.
Answer:
Step-by-step explanation:
A=2i+3j+4k
B=i-2j+3k
Sum of the vectors:
A + B = 2i+3j+4k + i-2j+3k = 3i + j + 7k
Direction of the sum of the vectors:
Answer:
d.
Step-by-step explanation:
The red graph is the black one times 2.
So y = 2 f(x). which is the same as y/2 = f(x) (divide by 2).
