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jekas [21]
3 years ago
11

Write the equation of a line that is parallel to Y=

Mathematics
2 answers:
zepelin [54]3 years ago
5 0

Answer:

The slope has to be the same so adjust the y-intercept.

Step-by-step explanation:

y=1/2x-10.5

Ivenika [448]3 years ago
3 0

<u>Answer: </u>

Equation of a line that is parallel to y=\frac{1}{2} x

and that passes through the point (9 -6) is \bold{y=\frac{1}{2} x+\frac{21}{2}}

<u>  Solution: </u>

The slope - intercept form equation of line is given as

\bold{y=mx+c}  --- (1)

Where m is the slope of the line. The coefficient of “x” is the value of slope of the line.

Given that

y=\frac{1}{2} x  ---- (2)

On comparing equation (1) and (2) we get slope of equation (2) is m = \frac{1}{2}

Consider equation of the line which is parallel to equation (1) is

y=m_{1} x+b --- (3)

If two lines are parallel then slope of both lines should be equal. That is if slope of the line (1) is \frac{1}{2} ,then slope of equation (3) is m_{1}=\frac{1}{2}

On substituting value of m1 in equation (3), we get

y=\frac{1}{2} x+b  --- (4)

Given that equation (4) passes through (9, -6) that is x = 9 and y = -6. So on substituting value of x and y in equation (4),

-6=\frac{9}{2}+b

On simplifying above equation,

b=\frac{9}{2}+6

b=\frac{9+12}{2}

b=\frac{21}{2}

On substituting value of b in equation (4),

y=\frac{1}{2} x+\frac{21}{2}

Hence equation of a line that is parallel to y=\frac{1}{2} x and that passes through the point (9 -6)  is \bold{y=\frac{1}{2} x+\frac{21}{2}}

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Passing through (-2, 8) and PERPENDICULAR to y = 2x + 5
tangare [24]

Answer:

y=\frac{-1}{2} x+7

Step-by-step explanation:

The slope of a perpendicular line will always be the NEGATIVE RECIPROCAL of the slope of the original line.

y=2x+5

Because this equation is organized in slope-intercept form, y=mx+b, we can identify the slope of the original line is 2. The negative reciprocal of 2 is \frac{-1}{2}. Therefore, the slope of the perpendicular line is \frac{-1}{2}. So far, our equation looks like this:

y=\frac{-1}{2}x+b

Now, we must solve for b, the y-intercept of this line. To do that, we can plug in the given point (-2,8) and solve for b:

y=\frac{-1}{2}x+b\\8=\frac{-1}{2}(-2)+b\\8=\frac{2}{2} +b\\8=1+b

Subtract both sides by 1 to isolate b

8-1=1+b-1\\7=b

Therefore, the y-intercept of this line is 7.

After plugging both the slope and the y-intercept into y=mx+b, we get:

y=\frac{-1}{2} x+7

I hope this helps!

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