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Katarina [22]
3 years ago
15

Jake can shoot 4 less than twice as many goals as Paul. If Jake shot 8 goals, how many did Paul shoot? ( I need an equation with

variable please )
Mathematics
1 answer:
Phoenix [80]3 years ago
7 0
P= Goals Shot By Paul

P2 - 4 = 8
     +4  +4
----------------
P2 = 12
---     ---
2        2
_______
P= 6

Paul shot 6 Goals :)
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Use the system of equations to answer the questions. 2x + 3y = 3, y = 8 - 3x. The value of y from the second equation is substit
Fittoniya [83]

Answer:

x=3 y=-1

Step-by-step explanation:

To get the value of x you need to put in the second equation which is y=8-3x as the y value for the first equation which is 2x+3y=3 making it

2x+3(8-3x)=3

2x+24-9x =3

24-7x =3

-7x=-21

Multiplying both sides by -7

x= 3

After getting an x value you substitute it in the equation in order to find your y value which is

2x+3y=3

2(3)+3y=3

3y=-3

Multiplying both sides by 3

y= <u>-3</u>

3

y=-1

7 0
3 years ago
Change the following into an ordinary decimal number: <br> 9.203 x 10 (to the power of) 6
Brilliant_brown [7]
Okay well since it is posivtive moe the decimal to the right the amount of times the power is. 9.203*10^6 ANSWER: 9,203,000
7 0
3 years ago
Read 2 more answers
BRANLIEST TO ANYONE WHO CAN DO THIS‼️‼️
Andrej [43]

Answer:

r = 1.293593 x 10^8  m

Step-by-step explanation:

r^2 = 167.3385 x 10^14

r = 12.93593 x 10^7  m

r = 1.293593 x 10^8  m

r = 1.293593 x 10^8  m

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What is the sum of angles a + b?
sladkih [1.3K]

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Step-by-step explanation:

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You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the
Vesna [10]

Answer:

A sample size of at least 1,353,733 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of .

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.  

You would like to be 98% confident that you esimate is within 0.1% of the true population proportion. How large of a sample size is required?

We need a sample size of at least n.

n is found when M = 0.001.

Since we don't have an estimate for the proportion, we use the worst case scenario, that is \pi = 0.5

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.001 = 2.327\sqrt{\frac{0.5*0.5}{n}}

0.001\sqrt{n} = 2.327*0.5

\sqrt{n} = \frac{2.327*0.5}{0.001}

(\sqrt{n})^{2} = (\frac{2.327*0.5}{0.001})^{2}

n = 1353732.25

Rounding up

A sample size of at least 1,353,733 is required.

5 0
3 years ago
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