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Hitman42 [59]
3 years ago
12

32×5 = 5× ? . I know 32×5 = 160, but I don't know how to solve the rest

Mathematics
2 answers:
RideAnS [48]3 years ago
5 0
The answer is x=32





I hope this helps
Virty [35]3 years ago
5 0
X=32 is the answer........
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What is the image point of (-6, 9) after a translation left 4 uints and down 1 unit?
Alex17521 [72]

Answer:

(-10,8)

Step-by-step explanation:

So our original point is (-6,9).

A translation of 4 units to the left means that the x-value would go left by 4. In other words, we subtract 4 to -6. We subtract because going to the left means that it's going to the negative direction.

A translation of down 1 unit means that the y-value would go down by 1. In other words, we subtract 1. Again, we subtract because going downwards means that it's going to the negative direction.

Therefore, the new point would be:

(-6-4,9-1)\\=(-10,8)

6 0
3 years ago
Which of the following is a sine of a in the right triangle below
seraphim [82]

Answer:

\frac{5}{13}

Step-by-step explanation:

sine of A = \frac{opposite}{hypotenuse}

opposite = 5

adjacent = 12

hypotenuse = 13

6 0
3 years ago
1. Reduce the ratio to the simplest form: <br> a)5:10=_____. <br> b)60:54=____.
Nikitich [7]

Answer:

1:2 by division of 5

10:9 by division of 6

6 0
2 years ago
Read 2 more answers
A single​ 6-sided die is rolled twice. The set of 36 equally likely outcomes is​ {(1,1), (1,2),​ (1,3), (1,4), left parenthesis
Dennis_Churaev [7]

Answer:

The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

Step-by-step explanation:

Given : A single​ 6-sided die is rolled twice.

To find : The probability of getting two numbers whose sum is greater than 9 and less than 13 ?

Solution :

The set of 36 equally likely outcomes,

          1              2              3              4               5             6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Getting two numbers whose sum is greater than 9 and less than 13

The favorable outcome is (4,6),(5,5),(5,6),(6, 4),(6, 5),(6, 6) = 6

The probability is given by,

\text{Probability}=\frac{\text{Favorable Outcome}}{\text{Total Outcome}}

\text{Probability}=\frac{6}{36}

\text{Probability}=\frac{1}{6}

Therefore, The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

5 0
4 years ago
Which is a infinitely many solution ?
Cerrena [4.2K]

Answer

Sorry thats not out topic yet

Step-by-step explanation:

Sorry :c

8 0
3 years ago
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