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3 years ago

32×5 = 5× ? . I know 32×5 = 160, but I don't know how to solve the rest

Mathematics

2 answers:

RideAnS [48]3 years ago

5 0

The answer is x=32

I hope this helps

Virty [35]3 years ago

5 0

X=32 is the answer........

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Graph: f(x) = (1/4)x

amid [387]

Answer: The initial value of a function is its value when equals zero. This is the same as the -intercept. We can see from the graph that our line crosses the -axis at the point zero, eight. Therefore, the initial value is eight.

Step-by-step explanation:

7 0

2 years ago

Can someone help me?

Ne4ueva [31]

Answer:

Step-by-step explanation:

All the interior angles are of measure 60 degrees.

We want to find the height of this triangle. Call it h. On the left side of this illustration is a right triangle with height h and base (1/2)(10), or 5.

The ratio of height to base is the tangent of 60 degrees:

tan 60 degrees = --------------

and tan 60 degrees = 1.73 = ------

Multiplying both sides of this equation by 5 yields h = 8.66. This is |BD|. This is the same as Answer B.

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3 years ago

Simplify.<br> Rewrite the expression in the form 4".<br> 49<br> 45

nexus9112 [7]

Answer:

$4^{9-5}$ = $4^{4}$

Step-by-step explanation:

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3 years ago

Find the length of side x in simplest radical form with a rational denominator.

Leto [7]

<h3>Answer: $2\sqrt{5}$ </h3>

======================================================

Explanation:

Both legs are the same length, as indicated by the tickmark.

a = $\sqrt{10}$
b = $\sqrt{10}$
c = x

Use the pythagorean theorem to solve for x

$a^2+b^2 = c^2\\\\( \sqrt{10} )^2 + ( \sqrt{10} )^2 = x^2\\\\10 + 10 = x^2\\\\x^2 = 20\\\\x = \sqrt{20}\\\\x = \sqrt{4*5}\\\\x = \sqrt{4}*\sqrt{5}\\\\x = 2\sqrt{5}\\\\$

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2 years ago

A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height

elena-s [515]

The formula is $s=-16t^2+V_ot$

We have:
$s=64$
$V_o=80ft/s$

Substituting these values into the formula, we have

$64=-16t^2+80t$

$16t^2-80t+64=0$ ⇒ divide each term by 16

$t^2-5t+4=0$ ⇒ find the pair of numbers that multiply to give 4 and sum gives -5 which is -1 and -4

$(t-1)(t-4)=0$ ⇒ We have two values of t

$t-1=0$ ⇒ $t=1$
$t-4=0$ ⇒ $t=4$

The time when the projectile reached 64 feet is at t=1 and t=4

6 0

3 years ago