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3 years ago

What is the slope of the line? y=2x-7

Mathematics

1 answer:

Ratling [72]3 years ago

4 0

The slope of the line is 2 because y=mx+b where m is slope and b is the y intercept

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Gomez found the masses of three rocks for a science project. The first rock had a mass of 19.28 grams the second rock had a mass

shusha [124]

1.72 because rocks 1 and 2 add up to 44.58 46.3-44.58=1.72

7 0

3 years ago

Read 2 more answers

The length of the shorter side of a parallelogram is 29 cm. Perpendicular line segment, which goes through the point of intersec

Katena32 [7]

A = 900 $cm^{2}$

The area of a parallelogram can be found by taking its base (b) and multiplying by the height (h). The base has the measure of 33 +12 = 45 cm. Now, you just need to find the height of the parallelogram. The height can be found by using the pythagorean theorem ( $a^{2} + b^{2} = c^{2}$ .

So, when simplified the height of the parallelogram will be found from $\sqrt{ 29^{2} - 21^{2}}$

The height is 20 cm. The base is 45 cm. 45 x 20 = 900.

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3 years ago

Evaluate 7 + (-3x^2) for x = 0. 4

Goshia [24]

Step-by-step explanation:

By substituting x = 0.4 in equation 7 + (-3x^2)

= 7 - 3 (0.4)^2

First solving o.4^2 as per the rule of BODMAS

= 7- 3 (0.16)

Now multiplying -3 with 0.16

= 7 - 0.48

= 6.52 THIS IS THE ANSWER

6 0

3 years ago

What us the slope of this line

KIM [24]

Answer:

slope = $\frac{1}{2}$

Step-by-step explanation:

Calculate slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (0, - 2) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = $\frac{0-(-2)}{4-0}$ = $\frac{0+2}{4}$ = $\frac{2}{4}$ = $\frac{1}{2}$

6 0

2 years ago

Simplify: –3(y + 2)2 – 5 + 6yWhat is the simplified product in standard form?

sweet-ann [11.9K]

Answer by Mimiwhatsup:

$\mathrm{Multiply\:the\:numbers:}\:3\cdot \:2=6\\=-6\left(y+2\right)-5+6y\\-6\left(y+2\right)\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=-6,\:b=y,\:c=2\\=-6y+\left(-6\right)\cdot \:2\\Apply\:minus-plus\:rules\\+\left(-a\right)=-a\\=-6y-6\cdot \:2\\\mathrm{Multiply\:the\:numbers:}\:6\cdot \:2=12\\=-6y-12\\=-6y-12-5+6y\\\mathrm{Simplify}\:-6y-12-5+6y\\Group\:like\:terms\\=-6y+6y-12-5\\\mathrm{Add\:similar\:elements:}\:-6y+6y=0\\=-12-5\\$

$\mathrm{Subtract\:the\:numbers:}\:-12-5=-17\\Answer is: =-17$

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3 years ago