Answer:
Step-by-step explanation:
![\displaystyle \frac{3\sqrt{3}}{2}a^2 = A \hookrightarrow \frac{3\sqrt{3}}{2}6^2 = A \\ \frac{3\sqrt{3}}{2}[36] = A; 54\sqrt{3}\:[or\:93,530743609...] \\ \\ \boxed{93,5 \approx A}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7Da%5E2%20%3D%20A%20%5Chookrightarrow%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7D6%5E2%20%3D%20A%20%5C%5C%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7D%5B36%5D%20%3D%20A%3B%2054%5Csqrt%7B3%7D%5C%3A%5Bor%5C%3A93%2C530743609...%5D%20%5C%5C%20%5C%5C%20%5Cboxed%7B93%2C5%20%5Capprox%20A%7D)
I am joyous to assist you at any time.
The steps involved in <span>practical problem solving are as follows:
</span><span>Assign an identifying variable to the quantity to be found.
</span>
<span>Write a sentence stating conditions placed on the quantity.
</span>
<span>Solve the sentence for the variable.</span>
Y(y+21) If you think about it you will see that it would most likely be this answer because the product of something is multiplying, and the sum is adding. If this answer is not correct then I am sorry.
we know that
tenths is equal to
% is equal to
so
tenths greater than% is equal to add
therefore
the answer is
