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aev [14]
3 years ago
11

Fill in the blank with a number to make the expression a perfect square. w? + 10w +

Mathematics
1 answer:
Over [174]3 years ago
6 0

\boxed{w^2+10w+25}

<h2>Explanation:</h2>

A Perfect-Square Trinomials are quadratics that result after squaring binomials. So these Perfect-square trinomials are given in the form:

a^2x^2\pm 2axb+b^2

Whose Squared-Binomial Form is:

(ax \pm b)^2

In this exercise, we have the variable w, so changing x \ by \ w it is true that:

a^2w^2\pm 2awb+b^2=(aw \pm b)^2

Therefore, for our given expression we have:

w?+10w+

So our goal is to complete this expression:

Step 1. First of all, we need to square our variable w. therefore:

w^2+10w+

Step 2. Here a=1

Step 3. Let's find b:

2wb=10w \\ \\ 2bw=10w \\ \\ So: \\ \\ 2b=10 \\ \\ Where: \\ \\ b=\frac{10}{2} \\ \\ \boxed{b=5}

Finally, our complete expression is:

\boxed{w^2+10w+25}

<h2>Learn more:</h2>

Factors of polynomials: brainly.com/question/1554148

#LearnWithBrainly

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Find the greatest common factor of 12m^2 and 9b^4
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2. What is the vertex of the following parabola? *
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A scale on a map shows that 2.52.52, point, 5 centimeters represents 151515 kilometers.
Dmitry_Shevchenko [17]

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  105 km

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Written as a proportion, the ratio of km to cm will be the same for both distances:

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5 0
3 years ago
In a study of parents' perceptions of their children's size, researchers asked parents to estimate their youngest child's height
tatyana61 [14]

Answer:

Test statistic t=6.505

P-value=0

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that parents tend to underestimate their youngest child's size.

Then, the null and alternative hypothesis are:

H_0: \mu=0\\\\H_a:\mu> 0

The significance level is assumed to be 0.05.

The sample has a size n=39.

The sample mean is M=7.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=7.2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{7.2}{\sqrt{39}}=1.153

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{7.5-0}{1.153}=\dfrac{7.5}{1.153}=6.505

The degrees of freedom for this sample size are:

df=n-1=39-1=38

This test is a right-tailed test, with 38 degrees of freedom and t=6.505, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>6.505)=0

As the P-value (0) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that parents tend to underestimate their youngest child's size.

5 0
3 years ago
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