Answer:
use cosine law
x^2 = 543^2 + 543^2 - 2(543)(543cos 128°
solve for x
Step-by-step explanation:
Let x be the mass of the paperbacks and y be the mass of the textbook.
20x + 9y = 44.4 ----------- (1)
25x + 10y = 51 -------------(2)
(1) x 10:
200x + 90y = 444 --------(1a)
(2) x 9:
225x + 90y = 459 --------(2a)
(2a) - (1a):
25x = 15
x = 0.6 -------- sub into (1)
20 (0.6) + 9y = 44.4
12 + 9y = 44.4
9y = 44.4 - 12
9y = 32.4
y = 3.6
So the paperback's mass is 0.6 pounds and textbook is 3.6 pounds
(4v-3w)∧2, Its to the second power so take the exponent 2 and put it on the variables and coefficients so you would have (4∧2)(v∧2)-(3∧2)(w∧2). Then you would do the math and get 16v∧2-9w∧2 than you would add the like terms so you have 25v∧2w∧2.
To find the distance between 2 numbers you must take the absolute value of the difference
|90-(-20)|
|110|
110
110 degrees celsius
Answer: B and C only
Step-by-step explanation:
The temperature on a cold day starts at 0 degrees Celsius, falls 4 degrees, and rises 4 degrees
Initial temperature = 0
Temperature rise = 4
Fall in temperature = - 4
(Initial temperature + rise in temperature + fall in temperature)
Summing all : (0 + 4 - 4) = 0
carbon atom has 6 negatively charged electrons and 6 positively charged protons.
Net charge of atom :
(number of proton + number of electrons)
( 6 + (-6)) = 0
