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Rudik [331]
3 years ago
12

I need some help on doing these :[ please and thank you ;-;

Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

is this geometry or algebra

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Find the x and the area of the shape perimeter is 64.5​
Umnica [9.8K]

Answer:

x=8

A = 192

Step-by-step explanation:

The perimeter is the sum of the outer lengths

17.9 + 22.6 + 3x = 64.5

Combine like terms

40.5 +3x = 64.5

Subtract 40.5 from each side

40.5 +3x -40.5 = 64.5 - 40.5

3x =24

Divide each side by 3

3x/3 = 24/3

x = 8

The area of a triangle is given by

A = 1/2 bh

The base is 3x = 3(8) =24

and the height is 2x = 2(8) =16

A = 1/2 (24) * 16

A =192

4 0
3 years ago
The radius of a. circular garden is 15 feet. About how much fencing will be needed to enclose the garden?
WINSTONCH [101]

Answer:

94.2 ft of fencing

Step-by-step explanation:

To answer this, find the circumference, C, of the garden, using the circumference formula C = 2(pi)r.

Here, with r = 15 ft, we get C = 2(3.14)(15 ft) = 94.2 ft of fencing will enclose this garden.

8 0
3 years ago
in 2006 ,the enrollment at jefferson high school was 1,200 students in 2012 the enrollment at jefferson high school was 1,650 st
Usimov [2.4K]
1650 - 1200 = 450
What percent is 450 of 1200?
y = 450/1200
y = 0.375
37.5% increase
3 0
3 years ago
Read 2 more answers
12.
IrinaVladis [17]

Answer:

Length of the room is   180 ft

Step-by-step explanation:

We have a rectangular room with dimensions:

width  =  70  ft       and  length    "x" (unknown)

Perimeter of a rectangle   is   2*w  +  2*x    and according to problem statement 500 ft of lights will fit exactly in room perimeter then:

2*70  +  2*x   =  500

140  + 2*x  =  500

2*x  =  500 - 140

2*x  = 360

x  = 360/2

x  =  180  ft

5 0
3 years ago
What are the zeros of the function f(x)=x^2-2x-15?
valkas [14]
To find the zeros of this function, we must first set the entire function equal to 0

f(x) = x² - 2x - 15 = 0

Since this is a quadratic function, we must use the quadratic formula, which is:

\frac{-b +/-  \sqrt{b^{2} - 4(a)(c) } }{2a}

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}

which simplifies to:

\frac{2 +/- \sqrt{(4 + 60} }{2}

Simplified further:

\frac{2 +/- \sqrt{(64} }{2}
\frac{2 +/- 8 }{2}
And divide it by the 2 on the bottom gives us:

2 +/- 4

2+4 = 6
2-4 = -2

So the zeros of this function are -2 and 6
6 0
3 years ago
Read 2 more answers
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