Missing information:
How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

Answer:

Step-by-step explanation:
Given




Express the given point P as a unit tangent vector:

Next, find the gradient of P and T using: 
Where

So: the gradient becomes:

![\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]](https://tex.z-dn.net/?f=%5Ctriangle%20T%20%3D%20%5B%28sin%20%5Csqrt%203%29i%20%2B%20%28cos%20%5Csqrt%203%29j%5D%20%2A%20%20%5B%5Cfrac%7B%5Csqrt%203%7D%7B2%7Di%20-%20%5Cfrac%7B1%7D%7B2%7Dj%5D)
By vector multiplication, we have:




Hence, the rate is:
Answer:
123
Step-by-step explanation:
idk
Answer:
41/100
Step-by-step explanation:
M = milk
C= cheese
X=meat
milk = 0.5c
meat = 4c
cheese = 1c
<span>4 +0.5 = 1c = 5.5c</span>
C= 42/5.5 = 7.64
X = 7.64 x 4 = 30.56
M =7.64 * 0.5 = 4.67
30.56 + 3.82 + 7.64 = approximately $42
Answer:
try this answer x2 + 2xy + y2 - 16